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3 years ago

5

Self-confidence, blank, and communication are key factors to building positive relationships. Fill in the blank with a 13 letter

word.

Computers and Technology

1 answer:

german3 years ago

6 0

Maybe: understanding, encouragement, <span>determination

there are many more, let me know if those don't work

</span>

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Explain which are of the brain you think might light up to show that you are telling a lie and why

agasfer [191]

The left side because the right side of the brain handles stuff more on the line of shapes and objects

6 0

3 years ago

List safety conditions when downloading shareware, free free where, or public domain software

Anit [1.1K]

Answer:

Explanation:

Freeware and shareware programs are softwares which are either free of charge or consist of a free version for a certain trial period. These programs pose a threat of habouring malware or viruses which could damage one's computer and important files and programs. Therefore, it is imperative that carefulness is maintained when trying to get these softwares.

Some of the necessary safety conditions that should be taken include;

1) Appropriate research about the software including taking more about the vendors and reviews.

2.) Once, a healthy review has been identified ; the download can begin with the Downloader ensuring that the download is from the recommended site.

3) Prior to installation the software should be scanned with an active anti-virus program to determine if there is possibility that a virus has creeped in.

4.) Some softwares may require that computer anti-virus be turned off during installation, this is not always a good idea as this act leaves the system vulnerable a d badly exposed.

6 0

2 years ago

Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have alre

Fudgin [204]

Answer:

The c++ program to implement the while loop is given below.

#include <iostream>

using namespace std;

int main() {

// declaration of integer variables

int k, n, total;

// initialization of integer variables

k=1, n=4, total=0;

// loop executed till value of k becomes equal to value of n

while( k <= n ){

// cube of every integer is added to the variable total

total = total + ( k * k * k );

// value of k is incremented to go to the next number

k = k + 1 ;

}

return 0;

}

Explanation:

The program begins with the declaration of integer variables.

int k, n, total;

This is followed by initialization of these variables.

k=1, n=4, total=0;

The while loop runs over the variable k which is initialized to 1. The loop runs till value of k reaches the value of integer n.

First, cube of k is computed and added to the variable total.

After first execution of the loop, total is initialized to the cube of 1.

Next, value of variable k is incremented by 1 so that k is initialized to next integer.

After first execution of the loop, k is incremented from 1 to 2.

while( k <= n )

{

total = total + ( k * k * k );

k = k + 1 ;

}

When the value of k reaches the value of integer n, the cube of n is calculated and added to the variable, total.

When k is incremented, it becomes more than n and hence, loop gets terminated.

As the return type of main is int, the program terminates with the statement shown below.

return 0;

No output is displayed as it is not mentioned in the question.

No user input is taken as it is mentioned that integer variables are already initialized.

4 0

2 years ago

Instructions Write a program that allows the user to enter the last names of five candidates in a local election and the number

KengaRu [80]

Here is code in java.

import java.util.*;

class Election

{ //main method

public static void main(String args[]){

// create an object of Scanner class to read input

Scanner s = new Scanner(System.in);

// string array to store name of candidates

String name[] = new String[5];

// int array to store vote count of candidates

int v_count[] = new int[5];

double p = 0;

int i = 0, sum = 0, high =0, win = 0;

for(i = 0; i < 5;i++)

{

System.out.print("last name of Candidate " + (i+1) + ":");

// read name of Candidate

name[i] = s.next();

System.out.print(" number of votes received: ");

// read vote of Candidate

v_count[i] =s.nextInt();

if(v_count[i] > high)

{

// highest vote

high = v_count[i];

win = i;

}

// total vote count

sum +=v_count[i];

}

// printing the output

System.out.println("\nCandidate\tVotes Received\t% of TotalVotes\n");

for(i = 0; i < 5;i++)

{

// % of vote of each Candidate

p =(v_count[i]*100)/sum;

// print the output

System.out.println(name[i] + "\t\t" + v_count[i] + "\t\t\t" +p);

}

// print the total votes

System.out.println("\nTotal Votes:\t" + sum);

// print the Winner of the Election

System.out.println("Winner of the Election is: " + name[win]);

}

}

Explanation:

Create a string array "name" to store the name of candidates.Create Integer array "v_count" to store votes os each candidates.Calculate total votes of all candidates and find the highest vote amongst all candidate and print it.Find % of votes received by each candidate.Print these stats.

Output:

last name of Candidate 1:patel

number of votes received: 54

last name of Candidate 2:singh

number of votes received: 76

last name of Candidate 3:roy

number of votes received: 33

last name of Candidate 4:yadav

number of votes received: 98

last name of Candidate 5:sharma

number of votes received: 50

Candidate Votes Received % of TotalVotes

patel 54 17.0

singh 76 24.0

roy 33 10.0

yadav 98 31.0

sharma 50 16.0

Total Votes: 311

Winner of the Election is: yadav

8 0

2 years ago

CHALLENGE ACTIVITY |

fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

double maxVal = 0.0;

if (num1 > num2) { // if num1 is greater than num2,

maxVal = num1; // then num1 is the maxVal. }

else {

maxVal = num2; // num2 is the maxVal. }

return maxVal; }

int main() {

double numA;

double numB;

double numY;

double numZ;

double maxSum = 0.0;

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

cout << "maxSum is: " << maxSum << endl; }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0 as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

6 0

2 years ago