Question

A. y = (x+3)^2-5

Answer 1

The vertex form of the parabola:

$f(x)+a(x-h)^2+k\\\\(h;\ k)-a\ vertex$

We have the coordinates of a vertex

$(-3;-5)\to h=-3;\ k=-5$

substitute:

$y=(x-(-3))^2+(-5)=(x+3)^2-5$

Answer: A. y = (x + 3)² - 5