Answer:
B
Explanation:
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Answer : The percent by mass of water the salt contain is, 55.3 %
Explanation : Given,
Mass of hydrated salt = 12.10 g
Mass of salt = 5.41 g
First we have to calculate the mass of water.
Mass of water = Mass of hydrate salt - Mass of salt
Mass of water = 12.10 g - 5.41 g
Mass of water = 6.69 g
Now we have to calculate the percent by mass of water the salt contain.

Now put all the given values in this expression, we get:


Therefore, the percent by mass of water the salt contain is, 55.3 %
If it goes from a volume of x, then when the volume is doubled it will go to a volume of 2x. If you meant what happens to the pressure, then the pressure halves as volume doubles due to Boyle's law.
Answer:
6.02×10²³ particles / 1 mol
Explanation:
In this question the choices are missed.
For determine the particles of Na, in 0.25 moles we should know that the mole referrs to the Avogadro's number.
1 mol of anything contains 6.02×10²³ entities, that's why we should apply this conversion factor to find the final answer:
0.25 mol . 6.02×10²³ particles / 1 mol = 1.50×10²³ particles
In conclussion: 1.50×10²³ particles of Na are contained in 0.25 moles of Na