Ask question

Ask question

All categories

3 years ago

5

find the area of one segment formed by a square with sides of 6 inches inscribed in a circle (hint: use the ratio of 1:1:square

root of 2 to find the radius of the circle)

1 answer:

alexgriva [62]3 years ago

5 0

Check the picture below.

You might be interested in

Rewrite in slope-intercept form and show your work.<br> -2x + 5y = 10

bearhunter [10]

Slope intercept form
y = mx + b
-2x + 5y = 10
5y = 2x + 10
Divide by 5
y = 2/5x + 2

8 0

3 years ago

Read 2 more answers

Joe and Josh each want to buy a video game. Joe has $14 and saves $10 a

Aleks [24]

Answer:

Number of week they have same amount = 4 week

Step-by-step explanation:

Given:

Amount Joe have = $14

Joe's saving per week = $10

Amount Josh have = $26

Josh saving per week = $7

Find:

Number of week they have same amount

Assume;

Number of week they have same amount = a

So,

(14 + 10a) = (26 + 7a)

3a = 12

a = 4

So,

Number of week they have same amount = 4 week

3 0

3 years ago

An international company has 19,500 employees in one country. If this represents 29.7% of the company's employees, how many empl

JulijaS [17]

Answer:

Sorry, Don't Know.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Subtract.<br> 8- (-5) <br> i cant find the answer to this

Furkat [3]

Answer:

13

Step-by-step explanation:

$8-(-5)=\\\\8+5=\\\\13$

Hope this helps.

4 0

4 years ago

Read 2 more answers

Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

6 0

2 years ago