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Thepotemich [5.8K]
3 years ago
8

Given A (-3,5) and B (6,7) find AB

Mathematics
1 answer:
allsm [11]3 years ago
4 0

Answer:2/9

Step-by-step explanation:

AB=\frac{7-5}{6+3}

    =\frac{2}{9}

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Answer:

x1, x2 = 7.73 , 4.27

Step-by-step explanation:

To find the roots of a quadratic function we have to use the bhaskara formula

ax^2 + bx + c

x^2 - 12x + 33

a = 1     b = -12    c = 33

x1 = (-b + √ b^2 - 4ac)/2a

x2 =(-b - √ b^2 - 4ac)/2a

x1 = (12 + √(-12^2 - (4 * 1 * 33))) / 2 * 1

x1 = (12 + √(144 - 132)) / 2

x1 = (12 + √12) / 2

x1 = (12 + 3.46) / 2

x1 = 15.46 / 2

x1 = 7.73

x2 = (12 - √(-12^2 - (4 * 1 * 33))) / 2 * 1

x2 = (12 - √(144 - 132)) / 2

x2 = (12 - √12) / 2

x2 = (12 - 3.46) / 2

x2 = 8.54 / 2

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8 0
3 years ago
What is the equation of the lines that passes through the points (-2, -3) and (4, -5)?
antoniya [11.8K]
Since all the options are in the slope intercept form, we find the equation using the formula,

y = mx + c
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m = \frac{ change \: in \: y }{change \: in \: x}
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On substitution,

y = - \frac{ 1}{3} x + c

We use any of the points, say (-2,-3) to determine the value of c.

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The equation is therefore,

y = - \frac{1}{3} x - \frac{11}{3}

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y+1=8/9(x+4)

Step-by-step explanation:

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