4 years ago

Answer both please I need help!!!!

Mathematics

1 answer:

tia_tia [17]4 years ago

3 0

The answers will be A for the first one and C for the second one.

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PLEASE SOLVE QUESTION 13 AND 14 DONT STEAL THE POINTS

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Answer:

See below for solution.

Step-by-step explanation:

$Q13)$ $\frac{\sqrt{11} - \sqrt{5} }{\sqrt{11}+\sqrt{5} }$ = $x - y\sqrt{55}$

LHS :-

= $\frac{\sqrt{11} - \sqrt{5} (\sqrt{11}-\sqrt{5}) }{\sqrt{11}+\sqrt{5} (\sqrt{11}-\sqrt{5}) }$

= $\frac{11-2\sqrt{55}+5 }{11 - 5}$

= $\frac{16-2\sqrt{55} }{6}$

= $\frac{2(8-\sqrt{55}) }{2(3)}$

= $\frac{8-\sqrt{55} }{3}$

=> x = 8/3 and y = 1/3

=> Option B

$Q14)$ $\frac{4}{216^{-2/3} }$ + $\frac{1}{256^{-3/4} }$ + $\frac{2}{243^{-1/5} }$

= 4 x (∛216)² + ( $\sqrt[4]256}$ )³ + 2 x ( $\sqrt[5]{243}$ )

= 4 x 36 + 64 + 2 x 3

= 144 + 64 +6

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