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3 years ago

Tenacious ran 12 miles in 2 hours. then he ran 36 miles in 3 hours. by how much did his rate increase

2 answers:

7 0

ANSWER

$6mph$

EXPLANATION

At first Tenacious ran 12 miles in 2 hours.

The rate at which he ran is the same as his speed.

$= \frac{12}{2} mph$
$= 6mph$

Now Tenacious ran 36 miles in 3 hours,

His new rate is

$= \frac{36}{3} mph$

$= 12mph$

Tenacious' rate increased from 6mph to 12mph.

Hence his rate increased by 6mph

frutty [35]3 years ago

4 0

Answer:

6 miles per hour increase

Step-by-step explanation:

12 miles in 2 hours is 12/2 = 6 miles per hour

36 miles in 3 hours 36/3 = 12 miles per hour

Take the 2nd rate and subtract the first rate

12 - 6 = 6 miles per hour increase

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Find the longitude and latitude for the points on the globe with angular coordinates ( θ , ϕ ) = ( π 4 , 11 π 12 ) (θ,ϕ)=(π4,11π

DedPeter [7]

Answer:

For (45,165.02) Latitude and longitude is (45 0' 0",165 1' 12")

Hence latitude and longitude are 4 degrees 35' 59.94" and 2 degrees 47' 59.994 "

Step-by-step explanation:

Given:

The angular coordinates of the point on globe as (θ,∅)=(π/4,11π/12)

To find : longitude and latitude for this points:

Solution:

For finding this Longitude and latitude we should convert it into decimal degrees

Given that 1rad =57.295 deg.

we get for

θ=π/4

=3.142/4

=0.7855 *57.295

=45 degrees.

Now for φ=11π/12

=(11*3.142)/12=2.8801*57.295

=165.02 degrees

Now convert in longitude and latitude as ,

as degrees +min/60+seconds/3600

Now latitude =45 degrees

i.e. 45 degrees 0' 0"

And longitude as

165.02 degrees becomes

165 degrees 1' 12".

Hence For the angular co-ordinates (45,165.02)

Longitude and latitude is (45 0' 0",165 1' 12")

Now for the (4.6, 2.8)

we get using same

degrees+min/60+seconds/3600

=4 degrees 35' 59.94"

And for 2.8 means, (similar to clock analog )

=2 degrees 47' 59.94"

Hence latitude and longitude are 4 degrees 35' 59.94" and 2 degrees 47' 59.994 "

8 0

4 years ago

Maria had 4 full cement blocks and one that was 5/9 the normal size if each full block weighed 3 8/9 pounds what is the weight

Vsevolod [243]

Answer:

17 and 58 over 81 pounds

Step-by-step explanation:

7 0

3 years ago

(Evaluating Expressions) If x = 1, y = 3, and z = 2, what is the value of the expression 4xy + 3xz + 7y? *

pshichka [43]

Answer:

Step-by-step explanation:

4 x 1 x 3 + 3 x 1 x 2 + 7 x 3

4 x 3 + 3 x 1 x 2 + 7 x 3

12 + 3 x 1 x 2 + 7 x 3

12 + 3 x 2 + 7 x 3

12 + 6 + 7 x 3

12 + 6 + 21

8 0

3 years ago

Solve the equation on the interval 0 less than or equals theta less than 2 pi .0≤θ<2π. secant StartFraction 5 theta Over 4 En

qaws [65]

Answer: 4π/15, 4π/3 and 28π/15 (in radians)

Step-by-step explanation:

$sec 5\theta/4 =2$

Recall that $sec \theta = 1/cos \theta$

$1/cos (5\theta/4) =2$

$cos (5\theta/4) =1/2$

$Cos^{-1}$ $\frac{1}{2}$ = $5\theta/4$

This implies that

$\mp60+360n=5\theta/4$

$\theta=4/5(\mp60+360n)= \mp48+288n$

$When n=0, \theta=48$

$When n=1, \theta=240, 336$

Therefore the values of $\theta$ between 0 and 2π are 48, 240 and 336. (All in degrees)

48 degrees= 4π/15 rad

240 degrees =4π/3 rad

336 degrees = 28π/15 rad

5 0

3 years ago

The function g(x) is a transformation of the cube root parent function,

asambeis [7]

Answer:

g(x) = $2(\sqrt[3]{x})$

Step-by-step explanation:

Parent function given in the graph attached is,

f(x) = $\sqrt[3]{x}$

Function 'f' passes through a point (1, 1).

If the parent function is stretched vertically by 'k' unit,

Transformed function will be,

g(x) = k.f(x)

Therefore, the image of the parent function will be,

g(x) = $k(\sqrt[3]{x})$

Since, the given function passes through (1, 2)

g(1) = $k(\sqrt[3]{1})$ = 2

⇒ k = 2

Therefore, image of the function 'f' will be,

g(x) = $2(\sqrt[3]{x})$

6 0

3 years ago