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love history [14]

3 years ago

6

Where in north american have the greatest risk of earthquake damage?

1 answer:

givi [52]3 years ago

4 0

That would be California as it lies on the most active fault in the US. Actually that whole area surrounding (Japan, Etc.) are all prone to earthquakes!

(Fun fact; I was planning a trip to Japan right before I started college but cancelled last minute, and then they say I was to arrive, the earthquake hit them.)

You might be interested in

Is relative humidity or dewpoint a better variable to examine to determine if there is sufficient moisture for thunderstorms to

skad [1K]

Answer:Relative humidity is a better

measure

Explanation:

Why? Because relative humidity measures the amount of moisture in the air compared to the current temperature of the air and what it can hold at that point. While few point merely measures the temperature of the air at which it reaches dew point and dew falls. . The basic conditions for a thunderstorm are moisture, unstable air and lift. It would be easier to read off moisture level in the air since relative humidity at 90 to 100 means it will rain more certainly than it will with dew point which may only mean that dew will fall.

5 0

3 years ago

An arc in this circle has a central angle of 162, degrees.

Phoenix [80]

Answer:

yes

Explanation:

8 0

3 years ago

Calculate the amount, in grams, of an original 300-gram sample of radioactive isotope Potassium-40 remaining after

Aleksandr [31]

Answer:

The current amount of the Potassium-40 sample is approximately 37.521 grams.

Explanation:

The amount of the sample of the radioactive isotope decays exponentially in time, the amount of mass of the sample as a function of time ( $m (t)$ ), in grams, is described below:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$ (1)

Where:

$m_{o}$ - Initial mass, in grams.

$t$ - Time, in years.

$\tau$ - Time constant, in years.

The time constant can be found from half life ( $t_{1/2}$ ), in years, described in statement:

$\tau = \frac{t_{1/2}}{\ln 2}$ (2)

If we know that $m_{o} = 300\,g$ , $t = 3.9\times 10^{9}\,yr$ and $t_{1/2} = 1.3\times 10^{9}\,yr$ , then the current amount of the sample is:

$\tau = \frac{1.3\times 10^{9}\,yr}{\ln 2}$

$\tau \approx 1.876\times 10^{9}\,yr$

$m = (300\,g)\cdot e^{-\frac{3.9\times 10^{9}\,yr}{1.876\times 10^{9}\,yr} }$

$m\approx 37.521\,g$

The current amount of the Potassium-40 sample is approximately 37.521 grams.

4 0

3 years ago

sanjay sold an article at a loss of 25 percent if the selling price had been increased by rs 175.there would have been gain of 1

vagabundo [1.1K]

Answer:

The cost price is Rs.500

Explanation:

<em>I'll approach this question by taking the statements in the question, one after the other</em>

Let the cost price be represented by CP

From the first statement:

Sanjay made a loss of 25%

The selling price (SP) is as follows;

$SP = CP - 25\% * CP$

Convert percent to fraction

$SP =CP - \frac{25}{100} * CP$

Get decimal equivalent

$SP = CP-0.25 * CP$

$SP = CP - 0.25CP$

$SP = 0.75CP$

From the second statement:

If the selling price was increased by 175%, Sanjay would make a profit of 10%

Hence; The new selling price is

$SP = 0.75CP + 175$

The selling price can also be calculated from the profit

$SP = CP + 10\% * CP$

Convert percent to fraction

$SP = CP + \frac{10}{100} * CP$

Get decimal equivalent

$SP = CP + 0.10 * CP$

$SP = CP + 0.10 CP$

$SP = 1.10 CP$

Equate both values of SP (SP = SP)

$1.10CP = 0.75CP + 175$

Collect Like Terms

$1.10CP - 0.75CP = 175$

$0.35CP = 1.75$

Divide both sides by 0.35

$CP = \frac{175}{0.35}$

$CP = 500$

<em>Hence, the cost price is Rs.500</em>

8 0

4 years ago

True or false the only weather conditions that we measure are the ones in the lower atmosphere

AveGali [126]

The answer to the question is true

5 0

4 years ago