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Juli2301 [7.4K]
2 years ago
10

HELP When 2((Three-fifths x + 2 and three-fourths y minus one-fourth x minus 1 and one-half y + 3)) is simplified, what is the r

esulting expression? 1 and StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6 StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6 StartFraction 7 over 10 EndFraction x + 8 and one-half y + 6 1 and StartFraction 7 over 10 EndFraction x + 4 and one-fourth y + 3
Mathematics
1 answer:
lesya692 [45]2 years ago
7 0

Answer:

<h2> StartFraction 7 over 10 EndFraction x + 2 and one-half y + 6</h2>

Step-by-step explanation:

Given the expression 2(\frac{3x}{5}+2\frac{3y}{4}-\frac{x}{4}-1 \frac{1}{2}y+3)

To simplify the expression, we need to first collect the like terms of the functions in parentheses as shown;

= 2(\frac{3x}{5}-\frac{x}{4}-1 \frac{1}{2}y+2\frac{3}{4}y+3)\\= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\

Then we find the LCM of the resulting function

= 2(\frac{3x}{5}-\frac{x}{4}- \frac{3}{2}y+\frac{11}{4}y+3)\\= 2(\frac{12x-5x}{20} - (\frac{6y-11y}{4})+3)\\= 2(\frac{7x}{20}- (\frac{-5y}{4})+3 )\\= 2(\frac{7x}{20}+ \frac{5y}{4}+3 )\\= \frac{7x}{10} + \frac{5y}{2} +6\\=  \frac{7x}{10} + 2\frac{1}{2}y+6\\

The final expression gives the required answer

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∠R and ∠S are complementary. If m∠R = (2x+7) and m∠S = (4x - 13), find m∠R
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Answer:

m∠R = 39 degrees

Step-by-step explanation:

As complementary angles add up to 90 degrees, we can set up an equation to get x then find the measure of ∠R:

m∠R + m∠S = 90

2x+7+4x-13=90

6x+7-13=90

6x-6=90

6x=96

x=16

Since m∠R = (2x+7), 2x+7 would be 2(16)+7 or 39 degrees. So in conclusion, m∠R = 39 degrees

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Step-by-step explanation:

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2 years ago
A balloon is released from a height of 10 feet. The balloon climbs an additional 70% of its previous height as each minute passe
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