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3 years ago

Can someone help me with these questions

Mathematics

2 answers:

STALIN [3.7K]3 years ago

6 0

The answer to 9 is C. 10 is A. 11 is B. and 12 is D.

Luda [366]3 years ago

4 0

The worksheet pic is not clear

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El valor de 2 – 3(5 + 2)(5 – 8) es

Margarita [4]

Answer:

Step-by-step explanation:

2 - 3 ( 5 + 2 ) ( 5 - 8 )

= 2 - 3 ( 7 ) ( -3 )

= 2 + 63

= 65

6 0

2 years ago

What is the equation of an asymptote of the hyperbola whose equation is (x-2)^2/4 - (y-1)^2/36 = 1?

UNO [17]

Answer: it’s C. Y=3x-5

4 0

3 years ago

There are three consecutive numbers such that twice the first is 20 more than the second.find the numbers? Show your solution.

xxTIMURxx [149]

Answering from phone so this will be a bit messy. a b=a+1 c=b+1=a+2 2a=b+20 Therefore: 2a=a+1+20 a=21,b=22,c=23

8 0

2 years ago

-1/4×3/5×-2/5 what dose this Equal

kipiarov [429]

Answer would be 3/50

5 0

3 years ago

Let T:ℝ2→ℝ2 be the linear transformation that first rotates points clockwise through 45∘ (????/4 radians) and then reflects poin

Alisiya [41]

Answer:

$T = \left[\begin{array}{ccc}-\frac{1}{\sqrt{2} } &\frac{1}{\sqrt{2} }\\\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\end{array}\right]$

Step-by-step explanation:

Let General Transformation matrix be denoted as T

Step 1: Clockwise rotation of 45 degrees

General counterclockwise rotation matrix in 2-dimension is given as

$R(\theta)=\left[\begin{array}{ccc}cos\theta & - sin\theta\\sin\theta&cos\theta\\\end{array}\right]$

For clockwise rotation we need to insert θ as negative in the above matrix. Therefore, the resulting matrix is

$R(-\theta)=\left[\begin{array}{ccc}cos\theta & sin\theta\\-sin\theta&cos\theta\\\end{array}\right]$

as sin(-θ) = -sin (θ) and cos(-θ) = cos (θ)

For 45 degrees

$sin(45) = \frac{1}{\sqrt{2} }$ and $cos(45) = \frac{1}{\sqrt{2} }$

$R(-45)=\left[\begin{array}{ccc}\frac{1}{\sqrt{2} } & \frac{1}{\sqrt{2} }\\-\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\\\end{array}\right]$

Step 2: Reflection through line y = x

This type of reflection maps (x,y)→(y,x)

Therefore the general matrix is

$R(x,y)=\left[\begin{array}{ccc}0&1\\1&0\end{array}\right]$

Step 3: General Transformation Matrix

T = R(x,y) R(-θ)

$T=\left[\begin{array}{ccc}0&1\\1&0\end{array}\right] \left[\begin{array}{ccc}\frac{1}{\sqrt{2} } & \frac{1}{\sqrt{2} }\\-\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\\\end{array}\right]$

$T = \left[\begin{array}{ccc}-\frac{1}{\sqrt{2} } &\frac{1}{\sqrt{2} }\\\frac{1}{\sqrt{2} }&\frac{1}{\sqrt{2} }\end{array}\right]$

3 0

2 years ago