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Yuliya22 [10]
3 years ago
6

H is the set of seven integers less than 10 but greater than or -8.

Mathematics
1 answer:
NNADVOKAT [17]3 years ago
7 0

(10 - 1) = 9
You might be interested in
Is x = 6 a solution to the equation 5(x – 3) = x + 13?
deff fn [24]

Answer:

x=6 is not a solution

Step-by-step explanation:

We can substitute 6 as x to find out:

5(6-3)=6+13

first, because of PEMDAS we'll do 6-3

5(3)=6+13

multiply 5 by 3 and add 6 and 13

15=19

Since the statement is not true, that means that x=6 is not a solution

Hope this helps!

8 0
3 years ago
Please help me on 7&8 and please show your work :)
Llana [10]
7. 6/12 or 1/2 | 8. 5/12

5 0
3 years ago
Plot the corresponding points for the inverse of the function represented by this table of values. x -4 0 3 7
NNADVOKAT [17]

Answer:

See explanation

Step-by-step explanation:

Given the function f(x) for which

\begin{array}{ccccc}x&-4&0&3&7\\ \\f(x)&9&5&2&-2\end {array}

If you want to plot the corresponding points for the inverse of the function f(x), change f(x) into y:  

\begin{array}{ccccc}x&-4&0&3&7\\ \\y&9&5&2&-2\end {array}

switch x and y

\begin{array}{ccccc}y&-4&0&3&7\\ \\x&9&5&2&-2\end {array}

and then change y into f^{-1}(x).

You get

\begin{array}{ccccc}x&9&5&2&-2\\ \\f^{-1}(x)&-4&0&3&7\end {array}

Now plot these points on the coordinate plane (see attached diagram).

3 0
2 years ago
Which method do you prefer to use to find sums- count by tens and ones, use compatible numbers, or use friendly numbers and adju
elena-s [515]
Count by tens and ones.
5 0
2 years ago
the first three steps of completing the square to solve the quadratic equation X2+4X-6=0 are shown below. what re the next 3 ste
Vilka [71]

Answer:

see the explanation

Step-by-step explanation:

<u><em>The complete question is</em></u>

The first three steps of completing the square to solve the quadratic equation x2 +4x -6= 0, are shown below.

Step 1: x2 +4x= 6

Step 2: x2 +4x+4=6+4

Step 3: (x +2)^2=10

What are the next 3 steps?​

we have

step 4

Take square root both sides

\sqrt{(x+2)^2} =\sqrt{10}

step 5

Simplify

x+2=\pm\sqrt{10}

step 6

Solve for x

subtract 2 both sides

x=-2\pm\sqrt{10}

x_1=-2+\sqrt{10}

x_2=-2-\sqrt{10}

3 0
2 years ago
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