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Nonamiya [84]
3 years ago
13

A male is heterozygous for the trait that produces freckles on the skin, and he has freckles. if he marries a woman who is also

heterozygous for freckles, ______ percent of their children are predicted to be freckled. also, of all their children, ______ percent are predicted to be heterozygous.
Biology
1 answer:
kakasveta [241]3 years ago
6 0
<span>F- allele for freckles
f- </span><span>allele without freckles

1) The man is heterozygote and has freckles, its indicating that the allele for freckles is dominant.
A cross between him and a woman who is also </span><span>heterozygote: Ff x Ff
it would result in the following probabilities:
- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff

Their son would have a probability of 75% of being born with freckles.


2) The cross resulted in this probabilities:
</span><span><span>- 1/4 - homozygote with freckles: FF
- 2/4 - </span><span>heterozygote with freckles: Ff
- 1/4- </span><span>homozygote without freckles:ff
So, the chance of being born heterozygote for this gene is 2/4, which is the same as half (50%).
</span></span>
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