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Vsevolod [243]
3 years ago
11

When finding out if 2 triangles are congruent, is it possible to only use a side and angle if those are the only 2 provided? Hel

p ASAP please.

Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0
Short answer: No and yes. 
Yes First.
If the lower right point (looks like an C perhaps or an F) and the middle point and the upper left point lie on the same line and if D the middle point and the upper right point lie n the the same line, then yes. You have angle side angle. The lower right angle is given as equal to the upper left angle. The angles at C are vertically opposite angles and they are equal and you have been given 2 enclosed sides that are equal.

No
If the points I've described are not on the same line, then the triangles are not congruent. If I can, I'll edit this a second time. 

Please Note:
You have done something that looks a bit illegal to me. I wouldn't just trade pictures. It only costs you another 5 points to issue another question. I do think, however, that it is very clever. In answering about 1700 questions, I've never seen this done. That's commendable.
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10/8-3/8=7/8

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What is the simplified form of (3.25x10^3)(7.8x10^6) written in scientific notation?
BabaBlast [244]

Answer: 2.535*10^{10}


Step-by-step explanation:

1. By definition, scientific notation has the following form:

a*10^{b}

Where:

<em> a</em> is a number between 1 and 10 but does not include 10.

<em> b </em>an integer.

2. When you multiply 3.25 by 7.8  the result is 25.35 and when you multiply 10^{3} by 10^{6}, you obtain 10^{9}, but to write ree thsult in scientific notation, the decimal point must be after the first digit. Therefore, you must move the decimal point one place to the left. So, the exponent changes from 9 to 10:

(3.25*10^{3})(7.8*10^{6})=2.535*10^{10}

3 0
2 years ago
Determine the asymptotes of the function: y=x^3-5x^2+4x-25/x^2-4x+3
igomit [66]

Answer:

Vertical A @ x=3 and x=1

Horizontal A nowhere since degree on top is higher than degree on bottom

Slant A @ y=x-1  

Step-by-step explanation:

I'm going to look for vertical first:

I'm going to factor the bottom first:  (x-3)(x-1)

So we have possible vertical asymptotes at x=3 and at x=1

To check I'm going to see if (x-3) is a factor of the top by plugging in 3 and seeing if I receive 0 (If I receive 0 then x=3 gives me a hole)

3^3-5(3)^2+4(3)-25=-31 so it isn't a factor of the top so you have a vertical asymptote at x=3

Let's check x=1

1^3-5(1)^2+4(1)-25=-25 so we have a vertical asymptote at x=1 also

There is no horizontal asymptote because degree of top is bigger than degree of bottom

There is a slant asympote because the degree of top is one more than degree of bottom (We can find this by doing long division)

                       x   -1

                --------------------------------------------------

x^2-4x+3 |      x^3-5x^2+4x-25

                  - ( x^3-4x^2+3x)

                   --------------------------------

                            -x^2 +x  -25

                       -   (-x^2+4x-3)

                          ---------------------

                                   -3x-22

So the slant asymptote is to x-1

8 0
3 years ago
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