Looks more like Trig than Algebra II
They want us to apply the sum angle formula to
5π/6 is 150°; I find it easier to think in degrees.
When the tangent of x is 3/4 that's a right triangle with opposite 3, adjacent 4 so hypotenuse 5. So a sine of 3/5 and a cosine of 4/5, both positive because we're told x is in the first quadrant.
The sine sum angle formula is
We know sin 150° = sin 30° = 1/2 and cos 150° = - cos 30° = -√3/2
Third choice
Using a trigonometric identity, it is found that the values of the cosine and the tangent of the angle are given by:
The identity that relates the sine squared and the cosine squared of the angle, as follows:
In this problem, we have that the sine is given by:
Hence, applying the identity, the cosine is given as follows:
The tangent is given by the sine divided by the cosine, hence:
More can be learned about trigonometric identities at brainly.com/question/24496175
#SPJ1
We are given zeros of the polynomial : 7, -11, and 2 + 8i.
Note: The radical zero always comes with the pair of plus and minus sign.
Therefore, another zero would be 2-8i.
Now, in order to find the polynomial with the zeros 7, -11, 2 + 8i and 2-8i, we need to find the factors of the polynomial.
The factors of the polynomial would be (x-7)(x+11)(x-2-8i)(x-2+8i).
Let us multiply those factors to get the standard form of the polynomial.
=
.