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Arte-miy333 [17]

3 years ago

11

A student looks through a microscope and sees a cell that contains a cell membrane, cytoplasm, mitochondria, and lysosomes. Whic

h organism was the student looking at?

1 answer:

ExtremeBDS [4]3 years ago

5 0

Answer:

i think its an animal cell

Explanation:

i may be wrong

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Who uses chemicals ?

nordsb [41]

Is there answer choices ??

4 0

2 years ago

Read 2 more answers

A certain reaction with an activation energy of 205 kj/mol was run at 485 k and again at 505 k . what is the ratio of f at the h

lapo4ka [179]

Arrhenius' Law relates activation energy, Ea, rate constant, K, and temperature, T as per this equation:

K (T) = A * e ^ (-Ea / RT), where R is the universal constant of gases and A is a constant which accounts for collision frequency..

Then you can find the ration between K's at two different temperatures as:

K1 = A * e ^ (-Ea / RT1)

K2 = A* e ^(-Ea / RT2)

=> K1 / K2 = e ^ { (-Ea / RT1) - Ea / RT2) }

=> K1 / K2 = e ^ {(-Ea/ R ) *( 1 / T1 - 1 T2) }

=> K1 / K2 = e^ { (-205,000 j/mol / 8.314 j/mol*k )* ( 1 / 505K - 1/ 485K) }

=> K1 / K2 = e ^ (2.0134494) ≈ 7.5

Answer: 7.5

8 0

2 years ago

9.25 * 10^21 pennies if how many moles

Brrunno [24]

According to Avogadro constant 1 mole = 6.02 x 10^23 what about 9.25 x10 ^21

that is 1 mole x ( 9.25 x10 ^21) / (6.02 x10^23) = 0.0154 moles

8 0

3 years ago

At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) equilibrium reaction arrow 2 HOCl(g) Calculate the concentration

wlad13 [49]

Answer:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.03901 mol/liter

[Cl₂O] = 0.02351 mol/liter

Explanation:

<u />

<u>1. Chemical reaction:</u>

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

<u>2. Initial concentrations:</u>

i) 1.3 g H₂O

Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol

Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter

ii) 2.2 g Cl₂O

Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol

Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter

<u>3. ICE (Initial, Change, Equilibrium) table</u>

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

I 0.0481 0.0326 0

C -x -x +x

E 0.0481-x 0.0326-x x

<u />

<u>4. Equilibrium expression</u>

$K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}$

$0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}$

<u />

<u>5. Solve:</u>

$x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0$

Use the quadatic formula:

$x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}$

The positive result is x = 0.00909

Thus the concentrations are:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter

[Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter

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2 years ago

When steelmakers add chromium and nickel to iron the result is

levacccp [35]

NNo chromium is more reactive than chromium because it it located farther right on the periodic table than nickel.. \nNo chromium is more reactive than nickel because it it located farther right on the periodic table than nickel.. \nNo chromium is more reactive than nickel because it it located f…

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3 years ago