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Soloha48 [4]
3 years ago
8

AAAAAAAAAAAAAA MATIAS IS HERERERERE

Chemistry
2 answers:
pochemuha3 years ago
8 0

Answer:

ENGLISH BOI ENGLISH!!!!!!!!!!

Explanation:

mariarad [96]3 years ago
7 0

Answer:

who?? is he a tiktoker?

Explanation:

You might be interested in
WEATHER PREDICTIONS FROM
fiasKO [112]

Answer:

These predictions are likely to be valid and should be needed.

Explanation:

Meteorologist made predictions about weather of a particular area on the data they received from the satellite. Meteorology is a branch of science in which we study about the atmosphere. It is mainly used for the forecasting of weather and meteorologists are those people or scientists who study the weather and research on different scales or instruments of weather.

7 0
3 years ago
a certain anesthetic contains 64.9% C, 13.5% H, and 21.6% O by mass. at 120 deg Celsius & 750 mmHg, 1.00 L of the gaseous co
slamgirl [31]
You need to use the % information to determine the empirical formula of the compound first. 

The empirical formula is the simplest ratio of atoms in the molecule. 

Then use the rest of the data to determine moles of gas, and use this to determine molar mass of gas... 

Empirical formula calculations:

Assume you have 100 g, calculate the moles of each atom in the 100 g 

moles = mass / molar mass 
molar mass C = 12.01 g/mol 
molar mass H = 1.008 g/mol 
molar mass O = 16.00 g/mol 

C = 64.9 % = 64.6 g 
H = 13.5 % = 13.5 g 
O = 21.6 % = 21.6 g 

moles C = 64.6 g / 12.01 g/mol = 5.38 mol 
moles H = 13.5 g / 1.008 g/mol = 13.39 mol 
moles O = 21.6 g / 16.00 g/mol = 1.35 mol 

So ratio of C : H : O 
is 5.38 mol : 13.39 mol : 1.35 mol 

Divide each number in the ratio by the lowest number to get the simplest whole number ratio 

(5.38 / 1.35) : (13.39 / 1.35) : (1.35 / 1.35) 

4 : 10 : 1 

empirical formula is 
C4H10O 


Finding moles and molar mass calcs 

Now, you know that at 120 deg C and 750 mmHg that 1.00L compound weighs 2.30 g. 

We can use this information to determine the molar mass of the gas after first working out how many moles the are in the 1.00 L 

PV = nRT 
P = pressure = 750 mmHg 
V = volume = 1.00 L 
n = moles (unknown) 
T = temp in Kelvin (120 deg C = (273.15 + 120) Kelvin) 
- T = 393.15 Kelvin 
R = gas constant, which is 62.363 mmHg L K^-1 mol^-1 (when your P is in mmHg and volume is in L) 

n = PV / RT 
n = (750 mmHg x 1.00 L) / (62.363mmHg L K^-1 mol^-1 x 393.15 K) 
n = 0.03059 moles of gas 

We know moles = 0.03509 and mass = 2.30 g 
So we can work out molar mass of the gas 

moles = mass / molar mass 
Therefore molar mass = mass / moles 
molar mass = 2.30 g / 0.03059 mol 
= 75.19 g/mol 


Determine molecular formula 

So empirical formula is C4H10O 
molar mass = 75.19 g/mol 

To find the molecular formula you divide the molar mass by the formula weight of the empirical formula... 
This tells you how many times the empirical formula fits into the molecular formula. Tou then multiply every atom in the empirical formula by this number 

formula weight C4H10O = 74.12 g/mol 

Divide molar mass by formula weight empirical 
75.15 g/mol / 74.12 g/mol 
= 1 
(It doesn't matter that the number don't quite match, they rarely do in this type of calc (although I could have made a slight error somewhere) but the numbers are very close, so we can say 1.) 

The empirical formula only fits into the molar mass once, 

molecular formula thus = empirical formula 
<span>
C4H10O

Therefore, the </span>molecular formula of the compound is <span>C4H10O.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
5 0
3 years ago
Air is made up mostly of O2, N2, and CO2. If the total pressure of air is 765mmHg and P(N2) = 0.79 atm and P(CO2) = 0.05 atm, th
Mrac [35]

Answer:

the partial pressure of the O2 is 0.167 atm

Explanation:

The computation of the partial pressure of the O2 is shown below:

As we know that

P = P_N2 + P_O2 + P_CO2

P_O2 = P - P_N2 -  P_CO2

= (1.007 - 0.79 - 0.05)

= 0.167 atm

Hence, the partial pressure of the O2 is 0.167 atm

we simply applied the above formula

5 0
3 years ago
Place the following molecular ions in order from smallest to largest bond order: <img src="https://tex.z-dn.net/?f=C_2%5E%7B2%2B
podryga [215]

Answer:

The correct answer is option 1 "F(2-) "less than" C2(2+) "less than" O(2-) "less than" N(2-)".

Explanation:

Bond order is a term used in chemistry to identify the number of electrons involved in making the bonding between two or more atoms in a molecule. Bond order is equal to half the difference between the number of bonds in the atoms minus the number of antibonds. Therefore, the correct order of bond order from smallest to largest is as follows:

1. F(2-): equals to 0.5 (it has 8 bonds and 7 antibonds)

2. C2(2+): equals to 1 (it has 4 bonds and 2 antibonds)

3. O(2-): equals to 2 (it has 8 bonds and 4 antibonds)

4. N(2-): equals to 2.5 (it has 8 bonds and 3 antibonds)

5 0
3 years ago
Potassium sulfate is added to water. The equation that best represents this process
Anastaziya [24]

The equation that best represents the addition of potassium sulfate to water is K_2SO_4(s) -- > 2 K^+ (aq) + SO4^{2-} (aq)

<h3>Dissolution of potassium sulfate in water</h3>

When potassium sulfate is dissolved in water, it dissociates into its cation and anion according to the following equation:

K_2SO_4(s) -- > 2 K^+ (aq) + SO4^{2-} (aq)

The positive ions are 2 moles of potassium ions while the negative ion is a mole of sulfate ion.

More on potassium sulfate can be found here: brainly.com/question/15405465

#SPJ1

5 0
2 years ago
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