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Angelina_Jolie [31]
3 years ago
14

Metals can be highly purified using electrolysis. Which equation best reflects the overall process of purifying copper?

Chemistry
2 answers:
WINSTONCH [101]3 years ago
7 0

Answer: The answer is D.  Cu(s)anode ---> Cu(s)cathode

Explanation: I just took the quiz

makvit [3.9K]3 years ago
3 0

Answer:

A. Cu^+2(aq)cathode ---> Cu^+2(aq)anode

Explanation:

Electrolysis is the process in which current is passed through a solution thereby causing a chemical change at the anode and cathode. Copper is being purified using electrolysis by using impure copper at the anode and pure copper at the cathode. This pure and impure copper are placed in a copper(ii)sulfate electrolyte solution and dc current is made to pass through it.  The resulting changes at the anode and cathode are given by the equation:

cathode: Cu²⁺  + 2e⁻    ⇒     Cu

anode:    Cu     ⇒       Cu²⁺  + 2e⁻

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2 years ago
Can somebody give me a example of a mixture?
exis [7]

I believe when you mix two things up together. It is called mixture. And they make one Compound. One example could be water, sugar, and flavorings making one compound which is soda. Hope it helps.

5 0
3 years ago
Read 2 more answers
How many moles of NaOH are present in 27.5 mL of 0.270 M NaOH?
Naddik [55]
The solution for the question above is:

C = 0.270 
<span>V = 0.0275L </span>
<span>n = ? </span>

<span>Use the molar formula which is: C = n/V </span>
<span>Re-arrange it to: n = CV </span>
<span>n = (0.270)*(0.0275) </span>
<span>n = 0.007425 mols </span>
<span>(more precise) n = 7.425 x 10^-3 mols
</span>
7.425 x 10^-3 mols is the answer.
8 0
3 years ago
A 1. 3×10−6mol sample of sr(oh)2 is dissolved in water to make up 25. 0 ml of solution. what is the ph of the solution at 25. 0∘
VMariaS [17]

The pH of the solution at 25 degree celsius of 1.3 × 10⁻⁶ moles of a sample of Sr(OH)₂ is 10.02.

<h3>How do we calculate pH?</h3>

The pH of any solution gives an idea about the acidic and basic nature of the solution and the equation of pH will be represented as:

pH + pOH = 14

Given that,

Moles of Sr(OH)₂ = 1.3 × 10⁻⁶ mol

Volume of solution = 25mL = 0.025L

The concentration of Sr(OH)₂ in terms of molarity = 1.3×10⁻⁶/0.025

                                                                                    = 5.2×10¯⁵M

Dissociation of Sr(OH)₂ takes place as:

                               Sr(OH)₂ → Sr²⁺ + 2OH⁻

From the stoichiometry of the reaction 1 mole of Sr(OH)₂ produces 2 moles of OH⁻.

Given that the base is a strong base and that it entirely dissociates into its ions, the hydroxide ion concentration is 5.2×10¯⁵×2 = 1.04×10¯⁴ M.

pOH = -log[OH⁻]

pOH = -log(1.04×10¯⁴)

pOH = 3.98

Now we put this value on the first equation we get,

pH = 14 - 3.98 = 10.02

Therefore, the value of pOH is 10.02.

Learn more about pH here:

brainly.com/question/24595796

#SPJ4

4 0
1 year ago
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