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olasank [31]
3 years ago
15

Help!! Need this question done in 20mins. I don't have a graphing calculator to give me the window screen!

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
6 0
2x - y = 1
2x + y = 7
-------------------add
4x = 8
x = 2

2x - y = 1
2(2) - y = 1
-y = -3
y = 3

answer (1,3)


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Only the a) part please!!!!
choli [55]

(i)\\\\2A = \begin{pmatrix}3x \times 2  & 1 \times 2 & 5 \times 2\\0\times 2 & 2x \times 2 & -3 \times 2\end{pmatrix} = \begin{pmatrix}6x & 2 & 10\\0 & 4x & -6\end{pmatrix}\\\\\\(ii)\\\\2A + B = C\\\\\implies  \begin{pmatrix}6x & 2 & 10\\0 & 4x & -6\end{pmatrix} + \begin{pmatrix}y & 0 & -4\\1 & -3y & 2\end{pmatrix} = \begin{pmatrix}31& 2 & 6\\1 & 17& -4\end{pmatrix}

\implies \begin{pmatrix}6x+y & 2+0 & 10-4\\0+1 & 4x-3y & -6+2\end{pmatrix} =  \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\\\implies \begin{pmatrix}6x+y & 2 & 6\\1 & 4x-3y & -4\end{pmatrix} =  \begin{pmatrix}31 & 2 & 6\\1 & 17& -4 \end{pmatrix}\\\\\text{System of equations},\\\\6x +y =31,~~ 4x -3y = 17\\\\\\(iii)\\\\6x +y-31 =0 \\\\4x-3y -17=0\\\\\text{Solving by cross multiplication method}\\\\\\\dfrac x{1(-17) - (-31)(-3)} = \dfrac y{4(-31) - 6(-17)} = \dfrac 1{6(-3) - 4(1)}

\implies \dfrac{x}{-17 -93}  = \dfrac{y}{-124 +102} = \dfrac 1{-18-4}\\\\\\\implies -\dfrac{x}{110} = -\dfrac{y}{22} = -\dfrac 1{22}\\\\ \implies \dfrac{x}{110} = \dfrac{y}{22} = \dfrac 1{22}\\\ \\\text{Hence,}\\\\\\x=\dfrac{110}{22}=5,~~~~ y= \dfrac{22}{22} =1

7 0
2 years ago
Read 2 more answers
Christopher rides his bike to and from school every day. The total distance he
Vitek1552 [10]

Answer

5 miles

Step-by-step explanation:

If he rides his bike one mile each day school to home each day its going to be 1 mile per day so if its 5 days it is 5 miles

8 0
3 years ago
Suppose you want to create a set of weights so that any object with an integer weight from 1 to 40 pounds can be balanced on a t
Archy [21]

Answer:

You need 4 weights, and the weights are 1; 3; 9 and 27.

Step-by-step explanation:

<em>Since the scale has two plates, we can place weights on either side and also the object so it can be balanced. </em>

This is a key part of the problem, it's not only on the other side of the scale, but on both sides.

Let's do the math now.

If i get two weights, 1 and 3. I can form this combinations.

Object of 1lb = 1

Object of 2lb + 1 weight = 3 weight.

Object of 3lb = 3 weight

Object of 4lb = 1 weight + 3 weight.

So what if i want to add the next weight and that weight to add me the maximum amount of objects. The weight would have to have a difference with the last object plus one. So if i grab 9. 9 minus 4 is 5. And that is a difference with the last object plus 1.

With a weight of 9, now i can add all the integers up to 13lb.

And the next step? Lets add one more. Keeping the last rule, the weight would have to have a difference with the last object plus one. So if i grab 27, 27 minus 13 is 14. And that is a difference witht the last object plus 1.

The sum of all the weights adds up to 40 pounds. And i can balance any integer in the middle.

The formula we are using is p – n = n + 1

Where p is the new weight. and n is the last object we weighted. And the sum of the weights goes up to the last object we can place on the scale, and in this case is 40.

4 0
3 years ago
SSC's Tuatara is the fastest car in the world with 331 miles per hour
Kipish [7]

Answer:

5.517miles/min

Step-by-step explanation:

331/1h

=331/(1*60) because 1h=60min

7 0
3 years ago
The area of a right triangle is 270 square meters. The height of the right triangle is 15 meters. What is the length of the hypo
soldi70 [24.7K]

Answer:

\sqrt{549} ≈ 23.4

Step-by-step explanation:

A = bh

270 = 15b

b = 18

Now you know the two legs, use the Pythagorean Theorem to find the value of the hypotenuse:  a² + b² = c²

15² + 18² = c²

225 + 324 = c²

c² = 549

c = √549

8 0
3 years ago
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