<em>f(3) = 13</em>
- Step-by-step explanation:
<em>f(x) = 2x + 7</em>
<em>replace </em><em>x</em><em> with </em><em>3</em>
<em>f(3) = 2×3 + 7</em>
<em>= 6 + 7</em>
<em>= 13</em>
Okay I will have an example for you. 3 and 2/7. STEP 1) multiply the denominator by the whole number. 3×7=21. STEP 2) add the numerator to 21. 21+2=23. STEP 3) 23 is the new numerator so put 23 over 7. FINAL SOLUTION 23/7.
Answer:
D
Step-by-step explanation:
According to remainder theorem, you can know the remainder of these polynomials if you plug in x = -6 into them.
<em>So we will plug in -6 into x of all the polynomials ( A through D) and see which one equals -3.</em>
<em />
<em>For A:</em>

For B:

For C:

For D:

The only function that has a remainder of -3 when divided by x + 6 is the fourth one, answer choice D.
Answer:
10 ft
Step-by-step explanation:
Square root of 100 = 10