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mihalych1998 [28]
3 years ago
10

How do you use Number patterns to find the least common multiple

Mathematics
1 answer:
Andrews [41]3 years ago
3 0
For example if the question asks what is the least common multiple of 2 and 3 you do 2: 1,2 3:1,3 You basically write out all the multiples and which ever one is the same and is the least is the answer! In this case the answer is one
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What is the following quotient? Sqrt 96/ Sqrt 8
Jobisdone [24]

Radicals cannot exist as a denominator, so you would multiply both Sqrt96 and Sqrt8 by the Sqrt8, giving you Sqrt768 over 8 (since a sqrt times itself is the base number, in this case 8) then you would simplify Sqrt768 into 16 x Sqrt3, leaving you with 16xSqrt3 over 8. simplify into 2Sqrt3 by dividing.

3 0
3 years ago
Read 2 more answers
Select the correct answer.
Marta_Voda [28]

Answer:  Step 5

===================================================

Reason:

The order of operations is PEMDAS

  • P = parenthesis
  • E = exponents
  • M = multiplication
  • D = division
  • A = addition
  • S = subtraction

The multiplication and division are on the same level of precedent, and the same goes for addition and subtraction. Some math textbooks may refer to PEMDAS as BODMAS, which is basically the same thing.

Notice how division comes before addition. So we must compute the 10 \div 2 portion first before adding in step 4.

This is what steps 4 and onward should look like

2 + 10 \div 2\\\\2 + 5\\\\7

So that's why the error is in <u>step 5</u>

If there was parenthesis around the "2+10", and we had (2+10) \div 2, then step 5 given by your teacher would be correct.

5 0
2 years ago
Which place could you round to so that rounded populations of all three cities are the same
Agata [3.3K]
You would round the hundreds.
but it depends what numbers there are of population like if you get into thousands round by thousand hundreds equals round by hundreds.

6 0
3 years ago
Read 2 more answers
An online video streaming service offers two plans for unlimited streaming. Plan A has a one-time $25 membership fee and is $8 p
GarryVolchara [31]

Answer:

so,what is the questions?

8 0
3 years ago
Consider two boxes, one containing one black and one white marble, the other, two black and one white marble. A box is selected
valina [46]

Answer:

\frac{7}{12}

Step-by-step explanation:

Probability refers to chance of happening of some event.

Conditional probability is the probability of an event A, given that another event B has already occurred.

B_1,B_2 denote the two boxes.

In box B_1:

No. of black balls = 1

No. of white balls = 1

In box B_2:

No. of black balls = 2

No. of white balls = 1

Let B, W denote black and white marble.

So, probability that either of the boxes B_1,B_2 is chosen is \frac{1}{2}

Probability that a black ball is chosen from box B_1 = \frac{1}{2}

Probability that a black ball is chosen from box B_2=\frac{2}{3}

To find:probability that the marble is black

Solution:

Probability that the marble is black = \frac{1}{2}(\frac{1}{2} )+\frac{1}{2}(\frac{2}{3})=\frac{1}{4}+\frac{1}{3}=\frac{7}{12}

6 0
3 years ago
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