Answer:
d is greater than c, since at 
Step-by-step explanation:
We are given two exponential functions, f and g.
Since f has the higher base(3 instead of 2 in g), it increases faster, so initially, g is greater than f, and after point (p,q), f is greater than g.
The values of c and d are found when 
. At this point, we have that g is greater than f, so d is greater than c.
Answer:
im not the best at algebra but
2a+3b+4c
Step-by-step explanation:
subtract
(2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).
add
=(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)
=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)
=4a+8c
then subtract
=(4a+8c)−(2a−3b+4c)
=4a+8c−2a+3b−4c
=2a+3b+4c
Answer:
Step-by-step explanation:
<h3><u>Given:</u></h3>
y = 12 cm
θ = 24°
Using trigonometric ratio, tan.
![\displaystyle \boxed{tan \theta = \frac{opposite}{adjacent} }\\\\tan \ 24 = \frac{x}{12} \\\\0.445 = \frac{x}{12} \\\\Multiply \ 12 \ to \ both \ sides\\\\0.445 \times 12 = x\\\\5.3 = x\\\\x = 5.3\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cboxed%7Btan%20%5Ctheta%20%3D%20%5Cfrac%7Bopposite%7D%7Badjacent%7D%20%7D%5C%5C%5C%5Ctan%20%5C%2024%20%3D%20%5Cfrac%7Bx%7D%7B12%7D%20%5C%5C%5C%5C0.445%20%3D%20%5Cfrac%7Bx%7D%7B12%7D%20%5C%5C%5C%5CMultiply%20%5C%2012%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C0.445%20%5Ctimes%2012%20%3D%20x%5C%5C%5C%5C5.3%20%3D%20x%5C%5C%5C%5Cx%20%3D%205.3%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Xmin: -10 Xmax: 10
Ymin: -10 Ymax: 10
32^(2c)=8^(c)+7
2^10c=2^3c+21 im gonna assume 7 is in the exponent
10c=3c+21
7c=21
c=3
