1. x^15
2. m^40
3. v^7/2
4. k^4
5. 1/x^14
6. 1/r^3/2
7. b^25
8. h^2
9. m^3n^1/7
10. x^12
11. 1/g^37
12. 1/100m^6
13. j^6/216
14. 1/125f^3
15. 3z^1/2
16. 1/100m^6
17. j^6/216
18.1/81d^20
19. 1
20. g^1/2 r^3
21. 16a^11
22. m^16n^21
23. 1
24. 1/y^10x^6
25. 343s^10/t^17/2
26.n^17/2 /m^10/2
27. 729/b^24c^9
28. 20y^2/x^33
Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125
Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50. #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5
The one of the left isn't too tricky, in the bottom left of it you have 1/2 of 1/4 of the shape, and on the bottom right you have 1/4 of 1/4. Imagine the whole shape was cut up like that bottom right bit into 16 triangles, then you would have three of them shaded (see my diagram).
The one on the right seems like guesswork to me, so I'm sorry if I'm wrong. It look like you just have to use your eyes to work out how much of the bottom half of the shape is shaded: looks like 1/16 to me (i.e. you can draw four of those along and four down, again, see my diagram.) So plus the top half, which is 8/16, you get 9/16.
Answers: left picture: 3/16.
right picture: 9/16.
So firstly, we have to find the LCD, or lowest common denominator, of 9 and 7. To do this, list the multiples of 9 and 7 and the lowest multiple they share is going to be your LCD. In this case, the LCD of 9 and 7 is 63. Multiply x^2/9 by 7/7 and 2y/7 by 9/9:

Next, add the numerators together, and your answer will be: 