Answer:
2.35 miles
Step-by-step explanation:
Answer:
f(2) = 0 and f(6) = -4
Step-by-step explanation:
First, find f(x) when x = 2
Plug in 2 as x in the function:
f(x) = -(x - 2)
f(2) = -(2 - 2)
f(2) = -(0)
f(2) = 0
Next, find f(x) when x = 6. Plug in 6 as x in the function:
f(x) = -(x - 2)
f(6) = -(6 - 2)
f(6) = -(4)
f(6) = -4
So, f(2) = 0 and f(6) = -4
Answer:
B. Beth's age is 18 years, and Sally's age is 42 years.
Step-by-step explanation:
You can solve this question in a couple of different ways. First, you can use process of elimination. You know that Sally is older than Beth because she has to be 3 times older 6 years ago, so you can get rid of options C and D because they both show Beth as being older. Now you only have A and B, and you can use a different process. Now from just looking at it, you can tell that A actually already shows Sally as 3 times Beth's age, 15 * 3 = 45. If you go to B, you can go ahead and subtract 6 from 18 (Beth's age) which will give you 12, and then multiply that by 3 to get 36. Now if you take 42 (Sally's age) and subtract 6 from it as well, you will get 36. This means that is lines up. To simplify, you are subtracting 6 from both 18 and 42, and then you are multiplying the lower number by 3 to see if it gets to the bigger number.
Hope this helped ^-^
Answer:
d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)
Step-by-step explanation:
d²y/dx² = (-2y² − x²) / (4y³)
Take the derivative (use quotient rule and chain rule):
d³y/dx³ = [ (4y³) (-4y dy/dx − 2x) − (-2y² − x²) (12y² dy/dx) ] / (4y³)²
d³y/dx³ = [ (-16y⁴ dy/dx − 8xy³ − (-24y⁴ dy/dx − 12x²y² dy/dx) ] / (16y⁶)
d³y/dx³ = (-16y⁴ dy/dx − 8xy³ + 24y⁴ dy/dx + 12x²y² dy/dx) / (16y⁶)
d³y/dx³ = ((8y⁴ + 12x²y²) dy/dx − 8xy³) / (16y⁶)
d³y/dx³ = ((2y² + 3x²) dy/dx − 2xy) / (4y⁴)
Substitute:
d³y/dx³ = ((2y² + 3x²) (-x / (2y)) − 2xy) / (4y⁴)
d³y/dx³ = ((2y² + 3x²) (-x) − 4xy²) / (8y⁵)
d³y/dx³ = (-2xy² − 3x³ − 4xy²) / (8y⁵)
Answer:
can u get a pic of the diagram
Step-by-step explanation:
