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lutik1710 [3]
3 years ago
11

What is the equation of the line through (1,6) and (0,2)

Mathematics
1 answer:
AlladinOne [14]3 years ago
7 0

Answer:

y=4x+2

Step-by-step explanation:

To find the slope of a line, you would do y₂-y₁/x₂x₁

This would be 2-6/0-1...

So your answer would be -4/-1

After simplifying, your slope is 4.

To write this in slope-intercept form, that would be y=4x+2

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sound travels 1,500 m/s through water at 25 degrees celciesunder these conditions how long would it take to travel 300m
Fantom [35]

Answer: it would take 18,00 M/S

Step-by-step explanation:

First you have to fined the unit rate

1,500/25= 60

Now your gonna do

300x60= 18,00

3 0
3 years ago
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Order - 11, 22, -10, 17, -26, and 1 from greatest to least.​
Ratling [72]
Greatest 22,17,1,-10,-11,-26 least
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3 years ago
(CO6) From a random sample of 68 businesses, it is found that the mean time that employees spend on personal issues each week is
satela [25.4K]

Answer:

(1) (4.82, 4.98)

(2) Large sample size

(3) Yes, the temperature is within the confidence interval of (37.40, 37.60)

(4) (15.083, 15.117)

Step-by-step explanation:

Confidence Interval (CI) = mean + or - (t×sd)/√n

(1) mean = 4.9, sd = 0.35, n = 68, degree of freedom = n-1 = 68 - 1 = 67

t-value corresponding to 67 degrees of freedom and 95% confidence level is 1.9958

CI = 4.9 + (1.9958×0.35)/√68 = 4.98

CI = 4.9 - (1.9958×0.35)/√68 = 4.82

CI is (4.82, 4.98)

(2) Error margin = (t-value × standard deviation)/√sample size

From the formula above, error margin varies inversely as the square root of the sample size. Since the relationship between the error margin and sample size is inverse, increase in one (sample size) will conversely lead to a decrease in the other (error margin)

(3) mean = 37.5, sd = 0.6, n= 100, degree of freedom = n-1 = 100-1 = 99

t-value corresponding to 99 degrees of freedom and 90% confidence level is 1.6602

CI = 37.5 + (1.6602×0.6)/√100 = 37.5 + 0.10 = 37.60

CI = 37.5 - (1.6602×0.6)/√100 = 37.5 - 0.10 = 37.40

37.53 is within the confidence interval (37.40, 37.60)

(4) mean = 15.10, sd =0.08, n = 104, degree of freedom = n-1 = 104-1 = 103

t-value corresponding to 103 degrees of freedom and 97% confidence interval is 2.2006

CI = 15.10 + (2.2006×0.08)/√104 = 15.10 + 0.017 = 15.117

CI = 15.10 - (2.2006×0.08)/√104 = 15.10 - 0.017 = 15.083

CI is (15.083, 15.117)

4 0
3 years ago
What is the answer to the solution 2x-y=5<br><br> A) 2,-1<br> B) 3,-1<br> C) 1,2<br> D) 7
lapo4ka [179]
I believe it's a , not sure though
6 0
3 years ago
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OleMash [197]
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2 years ago
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