Convention in algebra is that we use letters such as a, b, c, etc., for parameters and letters such as x, y z, and so on, for variables.
Thus the parameters here are a, b and k. k is the constant of proportionality.
So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
It’s c) XS, i love your pfp btw!! :)
Answer:
D
Step-by-step explanation:
y = 4 is a horizontal line which would be parallel to the x axis
Answer: y = -2|x| + 1
Step-by-step explanation: it is an absolute value function, y = |x|, moved up one. then we see that it has been flipped. it has also been vertically stretched by a factor of 2.
