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hammer [34]
3 years ago
8

What line is perpendicular to y= 2x - 4

Mathematics
1 answer:
kolezko [41]3 years ago
4 0
In Perpendicular product of slope is -1 so slope of y=2x-4 is 2 and 2*m=-1 m= -1/2 so y= -1/2x -4
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What is the inverse relation of the function whose equation is y= 3x-2
serg [7]

Answer:

1/3x +2/3 = y

Step-by-step explanation:

y= 3x-2

To find the inverse, exchange x and y

x = 3y-2

And solve for y

x+2 = 3y-2+2

x+2 = 3y

Divide by 3

1/3(x+2) = 1/3(3y)

1/3x +2/3 = y

6 0
3 years ago
to the nearest tenth what is the length of the hypotenuse of an isocoles right angle with a leg 7 3 inches
andrew11 [14]
If the two lengths are 7 and 3, then I believe the length of the hypotenuse would be approximately 7.62.
7 0
3 years ago
Jeff spent $7.50 at the store. He bought a notebook for $4.00. He also bought 10 pencils. How much did each cost?
DedPeter [7]
Subtract 7.50 - 4.00 and dived that answer by 10
7 0
4 years ago
Read 2 more answers
A manufacturer of shipping boxes has a box shaped like a cube. The side length is
Tatiana [17]
 The volume of a cube with side length equal to x, is V= x^{3}, 

thus, the volume of a cube shaped box, whose side length is (5a+4b) is :

V= (5a+4b)^{3},

The volume is already expressed in terms of a and b, but we can expand the expression (5a+4b)^{3}, as follows:

(5a+4b)^{3} =(5a+4b)(5a+4b)^{2}= (5a+4b)[ (5a)^{2}+2(5a)(4b)+ (4b)^{2}]

=(5a+4b)[ 25a^{2}+40ab+ 16b^{2}]

=(5a)[ 25a^{2}+40ab+ 16b^{2}]+(4b)[ 25a^{2}+40ab+ 16b^{2}]

=125a^{3}+200a^{2} b+ 80ab^{2}+100a^{2}b+160ab^{2} + 64b^{3}

125a^{3}+300a^{2} b+240ab^{2} + 64b^{3}


Answer:

V= (5a+4b)^{3},

or 

125a^{3}+300a^{2} b+240ab^{2} + 64b^{3}


7 0
3 years ago
f(t)=Q0(1+r)^t. Find the growth rate, r, to the nearest thousandth, given f(0.01)=1.06 and f(0.11)=1.09.
sweet-ann [11.9K]
To find the ratio, you just need to divide the two function and solve it. The calculation would be:

<span>F(t)=Q0(1+r)^t

F(0.11)/F(0.01)  =  1.09/1.06
</span>Q0(1+r)^0.11 / Q0(1+r)^0.01 = 1.0291
(1+r)^(0.11-0.01) =  <span>1.0291</span>
(1+r)^0.10  = 1.0291
(1+r)^0.10*10  =  1.0283 ^10
(1+r  )= 1.3325
r  = 0.323
4 0
3 years ago
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