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horrorfan [7]
3 years ago
10

A. Define what the numeric value of each group represents.

Mathematics
1 answer:
Masja [62]3 years ago
4 0

Answers:

A.  Box Plot 2 is very consistent and the datas are tight. Box Plot 2 is more spread and opened.

B.  Box Plot 1 has an outlier that makes the range of upper 25% of the data larger.

D.  Box Plot 2 is 75% the size Box Plot 1’s sections. Since the shape of Box Plot 1 is tighter, this means that Box Plot 2 have a lower deviation in the data numbers.

<em>This is the best I can do. Hope this helps!</em> :)

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You'd get this by multiplying the -10 by 3 then adding it to both sides. Then divide by 5. 
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PLEASE Help! <br><br> How much larger is 3 to the 5th power than 5 to the 3rd power?
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4 years ago
In a class of P students, the average of test scores is 70. In another class the average test scores is 92. When scores of the t
Basile [38]

So, since averages are defined as:

\frac{\sum_{k=1}^{P} P_k}{P}=70

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.

So, using that logic, the other class can be represented as:

\frac{\sum_{k=1}^{N} N_k}{N}=70

We can take both of these equations and multiply them by N:

\sum_{k=1}^{P} P_k=70P

\sum_{k=1}^N N_k=92N

So, if we want to find the average of this we should add both our equations then divide by P+N, which is the number of all the students.

\frac{\sum_{k=1}^{P} P_k+\sum_{k=1}^{N}N_k}{N+P}=\frac{70P+92N}{N+P}

To make this simpler we can replace our LHS with 86, since that's the average of both classes combined.

86=\frac{92N+70P}{N+P} \implies\\ 86N+86P=92N+70P \implies \\ 16P=6N \implies \\ \frac{16P}{N}=6 \implies \\ \frac{P}{N}=\frac{6}{16}

Simplified we would have P/N=3/8.

7 0
3 years ago
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