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andrey2020 [161]
3 years ago
6

With an interest rate of 3.25% over 4 years, how much money was originally deposited if

Mathematics
2 answers:
padilas [110]3 years ago
6 0
Interest = Principle(Rate)(Time)
$84.50 = P(0.0325)(4)
$84.50 = P(0.13)
$84.50/0.13 = P
P = 650

$650 was originally deposited.
vesna_86 [32]3 years ago
6 0

Answer: Amount of money originally deposited (P) = $650.0

Step-by-step explanation:

I = P x R x T/100

I = interest, P = Principal, R = Rate and T = Time.

I = $84.50, P = ?, R = 3.25%, T = 4

Making P the subject of the formul,a

P = I x 100/R x T

P = 84.50 x 100/3.25 x 4

P = 8450/13

P = $650.00

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A pizza is cut into five pieces. Four of the pieces are the same size, and the fifth size is .5 the size of each of the others.
Gemiola [76]

Answer:

1/10 of pizza

Step-by-step explanation:

Let x represent size of equal pieces.      

We have been given that a pizza is cut into five pieces. Four of the pieces are the same size, and the fifth size is 0.5 the size of each of the others.

This means that size of small piece would be half the size of other pieces, that is \frac{x}{2}.

Since the pizza is divided in 5 pieces, so we will divide \frac{x}{2} by 5 as:

\frac{\frac{x}{2}}{5}=\frac{x}{2\cdot5}=\frac{x}{10}=\frac{1}{10}x

Therefore, the smallest piece is 1/10 of the pizza.

8 0
3 years ago
How would the average rate of change over years 1 to 5 and years 6 to 10 be affected if the population increased at a rate of 8%
Sever21 [200]

Answer:

(A): As year increases the number of pikas reduces.

(B): As year increases the number of pikas increases as opposed to when the rate reduces.

Step-by-step explanation:

<em>See comment for complete question</em>

<u>Given</u>

a = 144 --- Initial Population

r = 8\% --- rate

<u>(A) WHEN THE RATE DECREASES</u>

First, we need to write out the function when the population decreases.

This is given as:

f(x) = a(1-r)^x

Substitute values for a and r

f(x) = 144(1-8\%)^x

Convert % to decimal

f(x) = 144(1-0.08)^x

f(x) = 144(0.92)^x

Next, we calculate the average rate of change for both intervals using:

Rate = \frac{f(b) - f(a)}{b-a}

For 1 to 5:

Rate = \frac{f(5) - f(1)}{5-1}

Rate = \frac{f(5) - f(1)}{4}

Calculate f(5) and f(1)

f(x) = 144(0.92)^x

f(1) = 144*0.92^1 =144*0.92=132.48

f(5) = 144*0.92^5 =144*0.66=95.04

Rate = \frac{95.04 - 132.48 }{4}

Rate = \frac{-37.44}{4}

Rate = -9.36

For 6 to 10:

Rate = \frac{f(10) - f(6)}{10-6}

Rate = \frac{f(10) - f(6)}{4}

Calculate f(6) and f(10)

f(x) = 144(0.92)^x

f(6) = 144*0.92^6 =144*0.61=87.84

f(10) = 144*0.92^{10} =144*0.43=61.92

Rate = \frac{61.92-87.84}{4}

Rate = \frac{-25.92}{4}

Rate = -6.48

So, we have:

Rate = -9.36 for year 1 to 5

This means that the number of pikas reduces by 9.36 yearly

Rate = -6.48 for year 6 to 10

This means that the number of pikas reduces by 6.48 yearly

So, we can say that, as year increases the number of pikas reduces.

<u>(B) WHEN THE RATE INCREASES</u>

First, we need to write out the function when the population decreases.

This is given as:

f(x) = a(1-r)^x

Substitute values for a and r

f(x) = 144(1+8\%)^x

Convert % to decimal

f(x) = 144(1+0.08)^x

f(x) = 144(1.08)^x

Next, we calculate the average rate of change for both intervals using:

Rate = \frac{f(b) - f(a)}{b-a}

For 1 to 5:

Rate = \frac{f(5) - f(1)}{5-1}

Rate = \frac{f(5) - f(1)}{4}

Calculate f(5) and f(1)

f(x) = 144(1.08)^x

f(1) = 144(1.08)^1 = 144*1.08= 155.52

f(5) = 144(1.08)^5 = 144*1.47= 211.68

Rate = \frac{211.68 - 155.52}{4}

Rate = \frac{56.16}{4}

Rate = 14.04

For 6 to 10:

Rate = \frac{f(10) - f(6)}{10-6}

Rate = \frac{f(10) - f(6)}{4}

Calculate f(6) and f(10)

f(x) = 144(1.08)^x

f(6) = 144(1.08)^6 = 228.52

f(10) = 144(1.08)^{10} = 310.89

Rate = \frac{310.89-228.52}{4}

Rate = \frac{82.37}{4}

Rate = 20.59

So, we have:

Rate = 14.04 for year 1 to 5

This means that the number of pikas increases by 14.04 yearly

Rate = 20.59 for year 6 to 10

This means that the number of pikas increases by 20.59 yearly

So, we can say that, as year increases the number of pikas increases as opposed to when the rate reduces.

5 0
3 years ago
PLEASE HELP!! if f(x)= 2x^2-11, find f(4)
Lemur [1.5K]

Answer: f(4) = 21

Step-by-step explanation:

2(4)^2-11

4^2 = 16

2(16)-11

Multiply 2 and 16

32 - 11

Subtract

21

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Answer:

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