3 years ago

(b) Factorise a² + 15a + 36

Mathematics

2 answers:

solmaris [256]3 years ago

5 0

(a+12)(a+3) should be right

ladessa [460]3 years ago

3 0

Answer: Hi

(a+3) (a+12)

Step-by-step explanation:

i hope this helps^_^

You might be interested in

What is the square root of 164

mote1985 [20]

I believe it is 12.8.

4 0

3 years ago

Read 2 more answers

Belinda's Great Dane is 74.Belinda's Great Dane is 74.9 cm tall and 225 cm long.

Svetlanka [38]

Answer:

0.749m and 2.25m

Step-by-step explanation:

to convert from centimeters to meters, you divide by 100 because there are 100cm in 1m

74.9cm/100= 0.749m and 225cm/100=2.25m

6 0

2 years ago

Ax+c=r Solve for x<br> Need help can anybody help?

kkurt [141]

What are the numbers for the other ones?

4 0

4 years ago

Read 2 more answers

What is the domain of the given function?

andrezito [222]

I have no idea tbh bro

7 0

3 years ago

Define f(0,0) in a way that extends f to be continuous at the origin. f(x, y) = ln ( 19x^2 - x^2y^2 + 19 y^2/ x^2 + y^2) Let f (

kirill115 [55]

Answer:

f(0,0)=ln19

Step-by-step explanation:

$f(x,y)=ln(\frac{19x^2-x^2y^2+19y^2}{x^2+y^2})$ is given as continuous function, so there exist $lim_{(x,y)\rightarrow(0,0)}f(x,y)$ and it is equal to f(0,0).

Put x=rcosA annd y=rsinA

$f(r,A)=ln(\frac{19r^2cos^2A-r^2cos^2A*r^2sin^2A+19r^2sin^2A}{r^cos^2A+r^2sin^2A})=ln(\frac{19r^2(cos^2A+sin^2A)-r^4cos^2Asin^a}{r^2(cos^2A+sin^2A)})$

we know that $cos^2A+sin^2A=1$ , so we have that

$f(r,A))=ln(\frac{19r^2-r^4cos^2Asin^a}{r^2})=ln(19-r^2cos^2Asin^2A)$

$lim_{(x,y)\rightarrow(0,0)}f(x,y)=lim_{r\rightarrow0}f(r,A)=ln19$

So f(0,0)=ln19.

8 0

3 years ago