3(x-1) = 2x - y
3x-3 = 2x-y
3x-2x+y = 3
x + y = 3 ----> (1)
2(x+y) = 3+3y
2x + 2y = 3 + 3y
2x + 2y - 3y = 3
2x - y = 3 -----> (2)
make equation (1) and (2) together
x + y + 2x - y = 3+3
3x = 6
x = 2
now make x = 2 in equation (1)
x + y = 3
2 + y = 3
y = 3-2
y = 1
(x,y) = (2,1)
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Answer:
The angle is 35
Step-by-step explanation:
The angles are vertical angles, so they are equal
3x-4 = 2x+9
Subtract 2x from each side
3x-2x-4 = 2x+9-2x
x-4 = 9
Add 4 to each side
x-4+4 = 9+4
x=13
But it asked for the measure of the angle
2x+9
2(13)+9
26+9
35
Answer:
The answer is below
Step-by-step explanation:
The equation of a straight line is given by:
y = mx + b
where m is the slope of the line and b is the y intercept (value of y when x = 0).
Given the equation of two lines as
, the two lines are parallel to each other if
. Also the lines are perpendicular if

Given line BC:
3x + 2y = 8
2y = -3x + 8
y = -3x/2 + 4
Hence the slope of the line BC = -3/2
For line AD:
-3x - 2y = 6
-2y =3x + 6
y = -3x/2 - 3
Hence the slope of line AD is -3/2
Since both line BC and AD have equal slope (-3/2), hence both lines are parallel to each other
Slope = 10/3 have a good day