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frutty [35]
2 years ago
5

I need know what is x .

Mathematics
2 answers:
lys-0071 [83]2 years ago
7 0

Answer:

21 x +6 =90⁰( Alternate exterior angles)

=) 21x =84

=) x =84/21 = 4

irina [24]2 years ago
3 0

Answer:

x is 4

Step-by-step explanation:

21x+6 = 90

21x=84

x=4

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The sum of the first n consecutive even numbers can be found using S = n2 + n, where n ≥ 2.
viktelen [127]
The following are the choices on this question:
 A.6
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The answer is option D. 12.

Check this out:
S=n² + n
S= 12² + 12
     (you can get the square of 12 by multiplying 12 by itself: 12 × 12)
S=144 +12
S=156
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3 years ago
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A rectangle is drawn on a coordinate plane. Three vertices of the rectangle are points L(−3,10) , M(6,10) , and P(−3,−6) . Point
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Hello!
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The answer is 16.
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3 years ago
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Parallelograms are four sided figures that have two pairs of opposite, parallel sides. Quadrilateral ABCD
otez555 [7]

Answer:

(A) It would have to lie on AB because DC would rotate halfway around M. B would lie on D and A would lie on C.

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8 0
2 years ago
There are 3 islands A,B,C. Island B is east of island A, 8 miles away. Island C is northeast of A, 5 miles away and northwest of
Nostrana [21]

Answer:

The bearing needed to navigate from island B to island C is approximately 38.213º.

Step-by-step explanation:

The geometrical diagram representing the statement is introduced below as attachment, and from Trigonometry we determine that bearing needed to navigate from island B to C by the Cosine Law:

AC^{2} = AB^{2}+BC^{2}-2\cdot AB\cdot BC\cdot \cos \theta (1)

Where:

AC - The distance from A to C, measured in miles.

AB - The distance from A to B, measured in miles.

BC - The distance from B to C, measured in miles.

\theta - Bearing from island B to island C, measured in sexagesimal degrees.

Then, we clear the bearing angle within the equation:

AC^{2}-AB^{2}-BC^{2}=-2\cdot AB\cdot BC\cdot \cos \theta

\cos \theta = \frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC}

\theta = \cos^{-1}\left(\frac{BC^{2}+AB^{2}-AC^{2}}{2\cdot AB\cdot BC} \right) (2)

If we know that BC = 7\,mi, AB = 8\,mi, AC = 5\,mi, then the bearing from island B to island C:

\theta = \cos^{-1}\left[\frac{(7\mi)^{2}+(8\,mi)^{2}-(5\,mi)^{2}}{2\cdot (8\,mi)\cdot (7\,mi)} \right]

\theta \approx 38.213^{\circ}

The bearing needed to navigate from island B to island C is approximately 38.213º.

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Step-by-step explanation:

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3 years ago
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