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3 years ago

write the equation of the line passing through the point (2,4) and parallel to the line whose equation is y=x.

1 answer:

7 0

Y = x....same as y = 1x + 0......slope here is 1. A parallel line will have the same slope

y = mx + b
slope(m) = 1
(2,4)....x = 2 and y = 4
now we sub and find b, the y int
4 = 1(2) + b
4 = 2 + b
4 - 2 = b
2 = b

so ur parallel equation is : y = x + 2

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Write an equation in slope-intercept form that goes through (12, 4) and (20,8).

spayn [35]

Answer:

Equation in slope-intercept form that goes through (12, 4) and (20,8) is: $y = \frac{1}{2}x-2$

Step-by-step explanation:

Given two points are:

$(x_1,y_1) = (12,4)\\(x_2,y_2) = (20,8)$

Slope intercept form of line is given as:

$y = mx+b$

Here m is the slope of the line and b is the y-intercept.

Slope of a line is calculated by the formula:

$m = \frac{y_2-y_1}{x_2-x_1}$

Putting the values

$m = \frac{8-4}{20-12}\\m = \frac{4}{8}\\m=\frac{1}{2}$

Putting the value of slope in slope-intercept form we get

$y = \frac{1}{2}x+b$

To find the value of b, any one point will be put in the equation

Putting the first point (12,4) in the equation

$4 = \frac{1}{2}(12) + b\\4 = 6+b\\b = 4-6\\b = -2$

Putting the value of b

$y = \frac{1}{2}x-2$

Hence,

Equation in slope-intercept form that goes through (12, 4) and (20,8) is: $y = \frac{1}{2}x-2$

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