Answer:
28 inches
Step-by-step explanation:
P = 2 (a + b) = 2 · (6 + 8) = 28
The length of the garden bed is 6 feet
<h3>The volume of a rectangular prism</h3>
The formula for calculating the volume of a rectangular prism is expressed as:
V = lwh
If turner and his grandfather used 18 bags of topsoil, each containing 3/4 of a cubic foot, to fill the bed completely, hence;
V = 3/4 * 18
V = 13.5 cubic foot
In order to determine the length of the garden;
135/10 = 9/2 * 1/2l
27/2 =9/4 l
18l = 27 * 4
18l = 108
l = 6 feet
Hence the length of the garden bed is 6 feet
Learn more on volume of rectangular prism here: brainly.com/question/24284033
822 hours. 10.25x822 is $8,425.50.
Answer:
No, the Roger’s claim is not correct.
Step-by-step explanation:
We are given that Roger claims that the two statistics most likely to change greatly when an outlier is added to a small data set are the mean and the median.
This statement by Roger is incorrect because the median is unaffected by the outlier value and only the mean value gets affected by the outlier value.
As the median represents the middlemost value of our dataset, so any value which is an outlier will be either at the start or at the end will not the median value. So, the median will not likely change when an outlier is added to a small data set.
Now, the mean is the average of all the data set values, that is the sum of all the observations divided by the number of observations. The mean will get affected by the outlier value because it take into account each and every value of the data set.
Hence, the mean will likely to change greatly when an outlier is added to a small data set.
Answer:
look below
Step-by-step explanation:
y = 2 (x + 3)^2 - 2
Geometric figure: parabola
Alternate forms:
y = 2 (x + 2) (x + 4)
y = 2 (x^2 + 6 x + 8)
-2 x^2 - 12 x + y - 16 = 0
Expanded form:
y = 2 x^2 + 12 x + 16
Roots:
x = -4
x = -2
<u>Properties as a real function:
</u>
Domain
- R (all real numbers)
Range
- {y element R : y>=-2}
Partial derivatives:
d/dx(2 (x + 3)^2 - 2) = 4 (x + 3)
d/dy(2 (x + 3)^2 - 2) = 0
Implicit derivatives:
(dx(y))/(dy) = 1/(12 + 4 x)
(dy(x))/(dx) = 4 (3 + x)
Global minimum:
min{2 (x + 3)^2 - 2} = -2 at x = -3