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Irina18 [472]
3 years ago
14

-37 - -47 gtfrtgyhbtgfvbnhjmrybgtsfvdcsx

Mathematics
2 answers:
Lilit [14]3 years ago
8 0

Answer:

{\huge{\mathfrak{\underbrace{\blue{Answer}}}}}

.

<h2><em>-</em><em>3</em><em>7</em><em>-</em><em> </em><em>-</em><em> </em><em>4</em><em>7</em><em>=</em><em>-</em><em>1</em><em>0</em></h2>

<em>.</em>

<em>I </em><em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

vesna_86 [32]3 years ago
3 0

Answer:

-37- -47=-10

Step-by-step explanation:

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Solve the equation<br>(5p-8)/2=(7p+4)/6​
ohaa [14]

Answer:

p=7/2=3.5

Step-by-step explanation:

(5p-8)/2=(7p+4)/6

cross product

2(7p+4)=6(5p-8)

14p+8=30p-48

8=30p-14p-48

8=16p-48

16p=8+48

16p=56

p=56/16

p=7/2=3.5

4 0
3 years ago
How many unique triangles can be drawn with side lengths 8 in., 12 in., and 24 in.? Explain. A. Any three sides form a unique tr
netineya [11]

Answer: C. Two of the side lengths add to a sum that is less than the third side length, so these lengths cannot be used to draw any triangles.

Explanation:

Those two sides in question are 8 and 12. They add to 8+12 = 20, but this sum is less than the third side 24. A triangle cannot be formed.

Try it out yourself. Cut out slips of paper that are 8 units, 12 units, and 24 units respectively. The units could be in inches or cm or mm based on your preference.

Then try to form a triangle with those side lengths. You'll find that it's not possible. If we had the 24 unit side be the horizontal base, so to speak, then we could attach the 8 and 12 unit lengths on either side of this horizontal piece. But then no matter how we rotate those smaller sides, they won't meet up to form the third point for the triangle. The sides are simply too short. Other possible configurations won't work either.

As a rule, the sum of any two sides of a triangle must be larger than the third side. This is the triangle inequality theorem.

That theorem says that the following three inequalities must all be true for a triangle to be possible.

  • x+y > z
  • x+z > y
  • y+z > x

where x,y,z are the sides of the triangle. They are placeholders for positive real numbers.

So because 8+12 > 24 is a false statement, this means that a triangle is not possible for these given side lengths. Therefore, 0 triangles can be formed.

6 0
3 years ago
ANSWER ASAP inequalities ​
Evgen [1.6K]
It’s option c. I hope that helped
6 0
3 years ago
3. Suppose that the interior angles of a convex hexagon are six
juin [17]

Answer:

The largest angle is A + 5 = 117.5 + 5 = 122.5 degree.  

Step-by-step explanation:

The sum of the interior angles of a regular hexagon is 720 degree.

Let the one angle is A.

So,

A + A + 1 + A + 2 + A + 3 + A + 4 + A + 5 = 720

6 A + 15 = 720

6 A = 705

A = 117.5

The largest angle is A + 5 = 117.5 + 5 = 122.5 degree.  

5 0
3 years ago
Find the missing sides of the given similar triangle​
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Provide an attachment so we can assist you.
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