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Juli2301 [7.4K]
3 years ago
11

If the square root of n is approximately equal to 4.2, then n is between _____.

Mathematics
2 answers:
Sliva [168]3 years ago
7 0

Answer:

16 and 25

Step-by-step explanation:

Given that the square root of n = 4.2, let's find an expression for this, then find the possible value of n.

Thus:

\sqrt{n} = 4.2

Solve for n. Square both sides.

(\sqrt{n})^2 = (4.2)^2

n = 17.64

Therefore, if the sqrae root of n was approximately equal to 4.2, then we can conclude that n is between 16 and 25.

kirill [66]3 years ago
6 0

Answer:

a

Step-by-step explanation:

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There are eight different jobs in a printer queue. Each job has a distinct tag which is a string of three upper case letters. Th
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Answer:

a. 40320 ways

b. 10080 ways

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Step-by-step explanation:

There are 8 different jobs in a printer queue.

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No. of ways to arrange the 8 jobs = 8!

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No. of ways to arrange the 8 jobs = 40320 ways

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c. First consider a gap of 1 space between the two jobs USU and CDP. One case can be that USU comes at the first place and CDP at the third place. The remaining 6 jobs can be arranged in 6! ways. Another case can be when USU comes at the second place and CDP at the fourth. This will go on until CDP is at the last place. So, we will have 5 such cases.

The no. of ways USU and CDP can be arranged with a gap of one space is:

6! * 6 = 4320

Then, with a gap of two spaces, USU can come at the first place and CDP at the fourth.  This will go on until CDP is at the last place and USU at the sixth. So there will be 5 cases. No. of ways the rest of the jobs can be arranged is 6! and the total no. of ways in which USU and CDP can be arranged with a space of two is: 5 * 6! = 3600

Then, with a gap of three spaces, USU will come at the first place and CDP at the fifth. We will have four such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 4 * 6!

Then, with a gap of four spaces, USU will come at the first place and CDP at the sixth. We will have three such cases until CDP comes last. So, total no of ways to arrange the jobs with USU and CDP three spaces apart = 3 * 6!

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e. If QKJ comes last then, the remaining 7 jobs can be arranged in 7! ways in the queue. Similarly, if QKJ comes second-to-last then also the jobs can be arranged in the queue in 7! ways. So, total no. of ways to arrange the jobs in the queue is 7! + 7! = 10080 ways

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