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marysya [2.9K]
3 years ago
13

To add the word "confidential" to the background of a page, users would need to _____.

Computers and Technology
2 answers:
maxonik [38]3 years ago
8 0
I believe it would be inserting a watermark (B)
mylen [45]3 years ago
4 0

Answer:

B . Insert. Watermark

Explanation:

You might be interested in
Write a Java program to encrypt and decrypt a phrase using two similar approaches, each insecure by modern standards. The first
xeze [42]

Answer:

See explaination

Explanation:

//CryptoManager.java

public class CryptoManager {

static int LOWER_BOUND=32;

static int UPPER_BOUND=95;

/*This method determines if a string is within the allowable bounds of ASCII

codes according to the LOWER_BOUND and UPPER_BOUND characters. The parameter

plainText is the string to be encrypted. The method returns true if all

characters are within the allowable bounds, false if any character is outside.*/

public static boolean stringInBounds (String plainText)

{

boolean flag=true;

//determines if a string is within the allowable bounds of ASCII

//codes according to the LOWER_BOUND and UPPER_BOUND characters.

for(int i=0;i<plainText.length();i++)

{

if(!((int)plainText.charAt(i)>=LOWER_BOUND && (int)plainText.charAt(i)<=UPPER_BOUND))

{ //false if any character is outside the bounds

flag=false;

break;

}

}

//returns true if all characters are within the allowable bounds

return flag;

}

/*This method encrypts a string according to the Caesar Cipher. The integer key

specifies an offset and each character in plainText is replaced by the character

the specified distance away from it. The parameter plainText is an uppercase

string to be encrypted. The parameter key is an integer that specifies the

offset of each character. The method returns the encrypted string.*/

public static String encryptCaesar(String plainText, int key)

{

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//encrypted text

String res="";

//encryption

for(int i=0;i<plainText.length();i++)

{

res+=Character.toString((char) ((int)plainText.charAt(i)+key));

}

//return result

return res;

}

/* This method decrypts a string according to the Caesar Cipher. The integer

key specifies an offset and each character in encryptedText is replaced by

the character "offset" characters before it. This is the inverse of the

encryptCaesar method. The parameter encryptedText is the encrypted string

to be decrypted, and key is the integer used to encrypt the original text.

The method returns the original plain text string.*/

public static String decryptCaesar(String encryptedText, int key){

//Wrap around the key, if it is greater than the UPPER_BOUND

key=Wrap_around(key);

//decrypted text

String org="";

//encryption

for(int i=0;i<encryptedText.length();i++)

{

org+=Character.toString((char) ((int)encryptedText.charAt(i)-key));

}

//return result

return org;

}

public static int Wrap_around(int key)

{

while(key>UPPER_BOUND)

{

key-=(UPPER_BOUND-LOWER_BOUND);

}

return key;

}

/* This method encrypts a string according to the Bellaso Cipher. Each character

in plainText is offset according to the ASCII value of the corresponding

character in bellasoStr, which is repeated to correspond to the length of

plaintext. The method returns the encrypted string.*/

public static String encryptBellaso(String plainText, String bellasoStr)

{

//encrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<plainText.length())

{

bellasoStr+=bellasoStr.substring(0,(plainText.length()-bellasoStr.length()));

}

//encryption

for(int i=0;i<plainText.length();i++)

{

char c=(char)Wrap_around((int)plainText.charAt(i)+(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

/*

This method decrypts a string according to the Bellaso Cipher. Each character

in encryptedText is replaced by the character corresponding to the character in

bellasoStr, which is repeated to correspond to the length of plainText. This is

the inverse of the encryptBellaso method. The parameter encryptedText is the

encrypted string to be decrypted, and bellasoStr is the string used to encrypt

the original text. The method returns the original plain text string.*/

public static String decryptBellaso(String encryptedText, String bellasoStr)

{

//decrypted text

String res="";

//Adjust length of bellasoStr to plainText

while(bellasoStr.length()<encryptedText.length())

{

bellasoStr+=bellasoStr.substring(0,(encryptedText.length()-bellasoStr.length()));

}

//decryption

for(int i=0;i<encryptedText.length();i++)

{

char c=(char)Wrap_around((int)encryptedText.charAt(i)-(int)bellasoStr.charAt(i) );

res+=Character.toString(c);

}

//return result

return res;

}

}

6 0
3 years ago
Resolution has the most impact on the size of photo print you can make.
siniylev [52]
If you want the best possible print, you need to upload the best quality digital file. Sometimes photos might look just fine when you look at them on your computer screen, and you might wonder what’s up with us when we say we can’t print them. Photos that don’t have sufficient resolution will look all blurry and pixilated (blocky with jagged edges) when printed.
3 0
4 years ago
Define and implement a method that takes a string array as a parameter and returns the length of the shortest and the longest st
Drupady [299]

Answer:

#HERE IS CODE IN PYTHON

#function to find length of shortest and longest string in the array

def fun(list2):

   #find length of shortest string

   mn=len(min(list2))

   #find length of longest string

   mx=len(max(list2))

   #return both the value

   return mn,mx

#array of strings

list2 = ['Ford', 'Volvo', 'BMW', 'MARUTI','TATA']

# call the function

mn,mx=fun(list2)

#print the result

print("shortest length is:",mn)

print("longest length is:",mx)

Explanation:

Create an array of strings.Call the function fun() with array as parameter. Here min() function will find the minimum string among all the strings of array and then len() function will find its length and assign to "mn". Similarly max() will find the largest string and then len() will find its length and assign to "mx". Function fun() will return "mn" & "mx".Then print the length of shortest and longest string.

Output:

shortest length is: 3

longest length is: 5

7 0
3 years ago
Type the correct answer in the box. Spell the word correctly.
aev [14]

Answer:if you are looking for video and audio data its mp4

Explanation:

there is no explaination

8 0
4 years ago
Read 2 more answers
Can Sombody please help me with this question, I'm struggling!
hjlf

Answer:

umm let me check if my answer is right

Explanation:

3 0
3 years ago
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