Answer: The maximum amount of magnesium oxide produced during the reaction can be, 3.9 grams.
Explanation : Given,
Mass of = 2.4 g
Mass of = 8.0 g
Molar mass of = 24.3 g/mol
Molar mass of = 31.9 g/mol
First we have to calculate the moles of and
.
and,
Now we have to calculate the limiting and excess reagent.
The balanced chemical equation is:
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.099 moles of react with
moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 2 mole of react to give 2 mole of
So, 0.099 mole of react to give 0.099 mole of
Now we have to calculate the mass of
Molar mass of = 40.3 g/mole
Therefore, the maximum amount of magnesium oxide produced during the reaction can be, 3.9 grams.