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Ann [662]
3 years ago
5

Decribe what happens to the.shape and volume of a solid a liquid and a gas when you place each into seperate closed containers c

hemistry
Chemistry
1 answer:
xeze [42]3 years ago
7 0
Solids have a definite shape and volume.

Liquids have a definite volume but not definite shape; it will take the shape of the container.

Gases have neither definite volume nor definite shape; it will fill the container evenly.
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Electrochemistry - Equilibrium
Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK  , F is faraday constant T is 273 + 25 = 298 K

E⁰cell  =  1.46 - 1.21 = .25 V

n = 2

Putting the values

.25 = (8.314 x 298  lnK) / (2 x 96485 )

lnK = 19.47

K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

n = 4

E⁰ = .4 + .83 = 1.23 V

Δ G ⁰= 4 x 1.23 x 96485

= 474706 J / mol

3 )

E⁰cell = (RT / nF ) lnK

n = 2

1.78 = 8.314 x 298  lnK / 2 x 96485

lnK = 138.638

K = 1.62 x 10⁶⁰

8 0
3 years ago
(ii) Describe another method for making ethanol.​
Aloiza [94]

Answer:

There are essentially three methods used to produce ethanol:

Manufacture from ethene using steam (the "synthetic" route)

Production from sugars and starches by fermentation, using yeasts.

Production from biomass waste, using bacteria.

Please give brainlist if this helped

7 0
3 years ago
The solubility of carbon dioxide in water is 0.161 g CO2in 100 mL of water at 20ºC and 1.00 atmCO2. A soft drink is carbonated w
Sedbober [7]

<u>Answer:</u> The solubility of carbon dioxide at 5.50 atm is 0.886g/100mL

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{A}=K_H\times p_{A}

Or,

\frac{C_{1}}{C_{2}}=\frac{p_{1}}{p_2}

where,

C_1\text{ and }p_1 are the initial concentration and partial pressure of carbon dioxide

C_2\text{ and }p_2 are the final concentration and partial pressure of carbon dioxide

We are given:

C_1=0.161g/100mL\\p_1=1.00atm\\C_2=?\\p_2=5.50atm

Putting values in above equation, we get:

\frac{0.161g/100mL}{C_2}=\frac{1.00atm}{5.50atm}\\\\C_2=\frac{0.161g/100mL\times 5.50atm}{1.00atm}=0.886g/100mL

Hence, the solubility of carbon dioxide at 5.50 atm is 0.886g/100mL

4 0
4 years ago
If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered un
Murrr4er [49]

Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

Explanation:

A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.

Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{36 g}{58.4 g/mol}\\= 0.616 mol

This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.

So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.

  • As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.

Moles = \frac{5.8 mol}{1000 mL} \times 100 mL\\= 0.58 mol

  • Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.

Moles = \frac{3.25 mol}{500 mL} \times 100 mL\\0.65 mol

  • Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.

Moles = \frac{1.85 mol}{300 mL} \times 100 mL\\= 0.616 mol

Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

8 0
3 years ago
What is the mass in grams of 5.2 moles of NaCl?<br> 303.89 g<br> 0.09 g<br> 119.6 g<br> 1828
Vitek1552 [10]

Explanation:

mole=mass/molar mass

mass= mole×molar mass

m= 5.2×( 23+35.5)

m= 5.2×58.5

m= 304.2g

6 0
3 years ago
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