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2 years ago

Help ASAP no links or I’m reporting only answer if you are confident and if you are correct

Chemistry

1 answer:

denpristay [2]2 years ago

8 0

Answer:

It's Brisbane.

Remember latitude and longitude.

27 degrees south is on the second bottom of the map (cities located beneath the equator). Also, 153 degrees east is located on the eastern side of the prime meridian. When pinpointing the location with these coordinates, you will find Brisbane

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Explanation:

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What do you call a bond between two neutral atoms that share electrons

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2 years ago

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Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calcu

stealth61 [152]

Answer:

Explanation:

Use one of your experimentally determined values of k, the activation energy you determined, and the Arrhenius equation to calculate the value of the rate constant at 25 °C. Alternatively, you can simply extrapolate the straight line plot of ln(k) vs. 1/T in your notebook to 1/298 , read off the value of ln(k), and determine the value of k. Please put your answer in scientific notation. slope=-12070, Ea=100kJ/mol, k= 0.000717(45C), 0.00284(55C), 0.00492(65C), 0.0165(75C), 0.0396(85C)

Explanation;

According to Arrhenius equation:

i.e. ln(k2/k1) = -Ea/R (1/T2 - 1/T1)

Where, k1 = 0.000717, T1 = 45 oC = (45+273) K = 318 K

T2 = 25 oC = (25 + 273) K = 298 K

i.e. ln(k2/0.000717) = -12070 (1/298 - 1/318)

i.e. ln(k2/0.000717) = -2.54738

i.e. k2/0.000717 = $e^{-2.54738}$

= 0.078286

Therefore, the required constant (k2) = 0.078286 * 0.000717 = $5.61*10^-^5$

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3 years ago

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Answer:-

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2 years ago

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siniylev [52]

Answer:

See explaination

Explanation:

please kindly see attachment for the step by step solution of the given problem.

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3 years ago