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Ne4ueva [31]
3 years ago
12

Which number has a 2 with a value ten times greater than the 2 in 5,621?

Mathematics
1 answer:
snow_lady [41]3 years ago
4 0
215.

The 2 in 5,621 is equal to 20 while 2 in 215 is equal to 200, which is ten times the prior one.
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HELP PLSSS
Gwar [14]

Answer:

LINE D

Step-by-step explanation:

4 0
3 years ago
What is the answer to this 2^2x =1/32
Alex73 [517]

Answer:

x=-\frac{5}{2}

Step-by-step explanation:

2^{2x}=\frac{1}{32}

2^{2x}=\frac{1}{2^5}

2^{2x}=2^{-5}

2x=-5

x=-\frac{5}{2}

8 0
2 years ago
Read 2 more answers
Based on the model, approximately how many customers will be on the restaurant when there are 10 cars parked in the restaurant’s
Zanzabum

Answer:

23

Step-by-step explanation:

From the graph, derive the best fit equation :

Using the points ;

(0,2.5)  (100 ,35)

x1 = 0 ; y1 = 2.5 ; x2 = 100 ; y2 = 35

Slope formula, m = (y2-y1)/(x2-x1)

m = (35-2.5)/(100-0)

m= (32.5)/100

m = 0.325

The y intercept, value on the graph where best fit line crosses the y axis = 2.5

The equation :

y = mx + c

c = intercept ; m = slope

y = 0.325x + 2.5

y = Number of cars

x = number of customers

The number of customers if there are 10 cars parked :

10 = 0.325x + 2.5

10 - 2.5 = 0.325x

7.5 = 0.325x

x = 7.5 / 0.325

x = 23.076

x = 23

6 0
3 years ago
16x what equals -112
fiasKO [112]

Answer:

-7

Step-by-step explanation:

16x=-112

x=-112/16

x=-7

PLS GIVE BRAINLIEST

5 0
2 years ago
Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1
sattari [20]
We have that

N 1)
a²<span> − 9a + 14 = 0 
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}


N 2) 

a²<span> + 9a + 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3) 

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}


N 4)

a²<span> + 5a − 14 = 0
</span>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}


N 5) 

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square  Remember to balance the equation by adding the same constants to each side 

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

3 0
3 years ago
Read 2 more answers
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