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Radda [10]
3 years ago
6

Which action is not a step in using paper folding to find the midpoint of a line

Mathematics
1 answer:
dedylja [7]3 years ago
5 0

Answer:

A. Draw a line from the segment to any point on the fold line.

Step-by-step explanation:

When using the paper folding method to find the midpoint of a line segment we take the following steps:

  1. Draw a line segment on the tracing paper
  2. Fold the tracing paper so that the endpoints lie on top of each other
  3. Mark the intersection of the fold and the segment with a point

These steps include statements B, C, and D. Drawing a line from the segment to any point on the fold line, which is statement A,  is not included in these steps because it is not needed.

Thus, choice A is not a step in using paper folding to find the midpoint of a line segment.

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last week you sold 30,45,50,75 and 80 units each day of the week in that order . On average how many units did you sell per day?
Butoxors [25]

Answer:

56 units

Step-by-step explanation:

add all numbers then divide by 5

30+45+50+75+80 = 280

280/5 = 56

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3 years ago
Solve the indicated variable 2(3n+4)=5n+8
Svetlanka [38]
N=0 is the answer for this problem
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3 years ago
A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are
IRINA_888 [86]

Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

5 percent of these are defective.

This means that p = 0.05

If two items are randomly selected as they come off the production line, what is the probability that both are defective

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025

0.0025 = 0.25% probability that both are defective

4 0
2 years ago
Make <br> x<br> the subject of the formula<br> x<br> +<br> 3<br> =<br> q
Anarel [89]

Answer:

x = q - 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

x + 3 = q

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 3 on both sides:          x = q - 3
7 0
3 years ago
Add. ( 3 4 x - 1) + ( 3 4 x - 2)<br> A) 1 <br> B) -3 <br> C) 3 2 x - 3 <br> D) 3 4 x + 1
DedPeter [7]
The answer would be C. hope that helps out :)
8 0
3 years ago
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