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3 years ago

How do we draw graphs in those kinds of questions?

Mathematics

1 answer:

just olya [345]3 years ago

5 0

Scan the equations in math-way and look at the graph

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C={X:X is even number X less than n equal to 7}<br>

sveta [45]

Answer:

Step-by-step explanation:

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3 years ago

Lines BC and ED are parallel. They are intersected by transversal AE, in which point B lies between points A and E. Lines BC and

Radda [10]

Answer: A

Step-by-step explanation:

3 0

2 years ago

Which system has no solution?<br> Check all that appy.

Ainat [17]

The first equation has no solution

The picture shows all the work I did, the reason I took a pic is because it is a little hard to explain by text, but I hope this helped you!

7 0

3 years ago

A baseball team has 4 pitchers, who only pitch, and 16 other players, all of whom can play any position other than pitcher. F

ivolga24 [154]

Answer:

2,075,673,600 batting orders may occur.

Step-by-step explanation:

The order of the first eight batters in the batting order is important. For example, if we exchange Jonathan Schoop with Adam Jones in the lineup, that is a different lineup. So we use the permutations formula to solve this problem.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

$P_{(n,x)} = \frac{n!}{(n-x)!}$

First 8 batters

8 players from a set of 16. So

$P_{(16,8)} = \frac{16!}{(16 - 8)!} = 518918400$

Last batter:

Any of the four pitchers.

How many different batting orders may occur?

4*518918400 = 2,075,673,600

2,075,673,600 batting orders may occur.

5 0

3 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$