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vredina [299]
3 years ago
9

How do we draw graphs in those kinds of questions?

Mathematics
1 answer:
just olya [345]3 years ago
5 0
Scan the equations in math-way and look at the graph
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Calculus help! Using the mean value theorem!
marta [7]
f is differentiable across its domain, so the MVT says there is some value of c in the open interval (a,b) such that

f'(c)=\dfrac{f(b)-f(a)}{b-a}

You have

f(x)=Ax^2+Bx+C\implies f'(x)=2Ax+B

so the equation above becomes

2Ac+B=\dfrac{(Ab^2+Bb+C)-(Aa^2+Ba+C)}{b-a}

Solve for c.

2Ac+B=\dfrac{A(b^2-a^2)+B(b-a)}{b-a}
2Ac+B=A(b+a)+B
2Ac=A(b+a)
c=\dfrac{b+a}2

so c is indeed the average of the endpoints, i.e. the midpoint.
8 0
3 years ago
Answer the question on the image <br><br><br><br> ty :P
sattari [20]
Answer : 7 or 7/1

step by step explanation:
6 0
3 years ago
For which value of theta is cot (theta) undefined?
sattari [20]

The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.


\cot(x) = \frac{\cos(x)}{\sin(x)}


Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.


Let's look at your option:


\sin(90^\circ) = 1, so the cotangent is defined here


\sin(180^\circ) = 0, so the cotangent is not defined here


\sin(270^\circ) = -1, so the cotangent is defined here


\sin(450^\circ) = \sin(360^\circ+90^\circ)=\sin(90^\circ) = 1, so the cotangent is defined here

6 0
3 years ago
Read 2 more answers
Which is a perfect square?<br>6^1<br>6^2<br>6^3<br>6^5<br>Need the answer asap​
oksian1 [2.3K]

Answer:

The answer is 6²

Step-by-step explanation:

Since 6² = 36

√36 = 6 making 6² a perfect square.

Hope this helps you

4 0
3 years ago
Read 2 more answers
Hi, I need help with this question. Here is the question: For which data set is the median greater than the mean?
FinnZ [79.3K]

Answer:

Set 2

Step-by-step explanation:

First find the median of each set (the median being the number in the middle):

(1) { 4,7,10,13,16} = 10

(2) {8,9,10,18,19} = 10

(3) {8,9,10,11,12} = 10

(4) {1,2,10,11, 12} = 10

Then find the mean of each set (the mean being average of all the numbers, to find the average add up all the numbers and divide by the amount of numbers):

(1) { 4,7,10,13,16} = 10

(2) {8,9,10,18,19} = 12.8

(3) {8,9,10,11,12} = 10

(4) {1,2,10,11, 12} = 7.2

the answer being 12.8 since 12.8 is greater than 10

4 0
3 years ago
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