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vredina [299]
3 years ago
9

How do we draw graphs in those kinds of questions?

Mathematics
1 answer:
just olya [345]3 years ago
5 0
Scan the equations in math-way and look at the graph
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Tìm x,y thỏa mãn: x^2-2xy+3y-5x+7=0
STALIN [3.7K]

I think there's an error with this question. Mind to check it back and tell me the detail?

7 0
3 years ago
Ihorangi travels 51 km to work and 51 km from work each day.
viktelen [127]

Answer:

Ihorangi uses 7.65 litres of petrol to and from work

Step-by-step explanation:

If the car Ihorangi drives consumes 7.5 L/100 km

Then for 1 km journey, the car will consume 7.5/100 L

= 0.075 L

If Ihorangi travels 51 km to work and 51 km from work

Therefore Ihorangi travel (51 + 51) km daily to and from work

= 102 km daily

The fuel he consumes daily is 102*0.075 L

= 7.65 L

7 0
3 years ago
Explain Well please.
Art [367]
The answer is C,
as she uses SSS to prove its congruent, she uses sides instead of angles so option a and d is not correct. as it needs to prove triangle pqr is congruent to triangle sqr, its not necessary to prove PQ is equal to QR. so the answer is c
7 0
3 years ago
The polar coordinates of a point are 3π 4 and 7.00 m. What are its Cartesian coordinates (in m)? (x, y) = 6.06,−3.5 m
Keith_Richards [23]

Answer:

a) \left(x,y\right)=\left(4.95,-4.95\right)

b) r\angle\theta = 7\angle0.5236\,\text{radians}

Step-by-step explanation:

Polar coordinates are represented as: r\angle\theta, where 'r' is the length (or magnitude) of the line, and '\theta' is the angle measured from the positive x-axis.

in our case:

7\angle\dfrac{3\pi}{4}

to covert the polar to cartesian:

x = r\cos{\theta}

y = r\sin{\theta}

we can plug in our values:

x = 7\cos{\dfrac{3\pi}{4}} = -7\dfrac{\sqrt{2}}{2}

y = 7\sin{\dfrac{3\pi}{4}} = 7\dfrac{\sqrt{2}}{2}

the Cartesian coordinates are:

\left(x,y\right)=\left(-7\dfrac{\sqrt{2}}{2},7\dfrac{\sqrt{2}}{2}\right)

\left(x,y\right)=\left(4.95,-4.95\right)

(b) to convert (x,y) = (6.06,-3.5)

we'll use the pythagoras theorem to find 'r'

r^2 = x^2+y^2

r^2 = (6.06)^2+(-3.5)^2

r = \sqrt{48.97} \approx 7

the angle can be found by:

\tan{\theta} = \dfrac{y}{x}

\tan{\theta} = \dfrac{3.5}{6.06}

\theta = \arctan{left(\dfrac{3.5}{6.06}\right)}

\theta = 0.5236 \text{radians}

to convert radians to degrees:

\theta = 0.5236 \times \dfrac{180}{\pi} \approx 30^\circ

writing in polar coordinates:

r\angle\theta = 7\angle30^\circ\,\,\text{OR}\,\,7\angle0.5236\,\text{radians}

5 0
3 years ago
I need some help on this question. Segment LM is the midsegment of trapezoid ABCD. AB=48, and DC=88. What is LM? I am not sure h
agasfer [191]
AB=48, DC=88

48+88=136
136÷2=68

Answer: LM=68
Remember that the length of the mid segment in a trapezoid is half the sum of the base lengths.
4 0
4 years ago
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