Answer:
Refer the attached figure.
Step-by-step explanation:
Given : The quadratic equation - ![f(x)=x^2-8x+24](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-8x%2B24)
To find : The graphic representation of the quadratic function ?
Solution :
We plot the graph of quadratic equation,
The standard form of equation is ![y=ax^2+bx+c](https://tex.z-dn.net/?f=y%3Dax%5E2%2Bbx%2Bc)
Comparing with given equation, ![f(x)=x^2-8x+24](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-8x%2B24)
a=1 , b=-8 , c=24
Axis of symmetry is ![x=-\frac{b}{2a}](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7Bb%7D%7B2a%7D)
The axis of symmetry of given equation is ![x=-\frac{-8}{2(1)}=4](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B-8%7D%7B2%281%29%7D%3D4)
The vertex form of quadratic equation is ![f (x) = a(x - h)^2 + k](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20a%28x%20-%20h%29%5E2%20%2B%20k)
Where, (h,k) are the vertex.
Convert the quadratic equation into vertex form,
By completing the square,
![f(x)=x^2-8x+24](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-8x%2B24)
![f(x)=(x^2-2(4)x+(4)^2)-(4)^2+24](https://tex.z-dn.net/?f=f%28x%29%3D%28x%5E2-2%284%29x%2B%284%29%5E2%29-%284%29%5E2%2B24)
![f(x)=(x-4)^2+8](https://tex.z-dn.net/?f=f%28x%29%3D%28x-4%29%5E2%2B8)
On comparison,
(h,k)=(4,8)
Now, we plot the equation with vertex (4,8).
Refer the attached figure below.