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2 years ago

If someone could help me on this, that would be great. Thanks.

Mathematics

2 answers:

Dovator [93]2 years ago

8 0

Answer:

A. distributive property

Alisiya [41]2 years ago

3 0

Answer:. Distributive property

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3. A dish contains 100 candies. Juan removes candies from the dish each day and no

iVinArrow [24]

Answer:

Step-by-step explanation:

If i am correct n= the days so with the days adding up day 10 juan would have 55 of the 100 candies, day 11 he would have 66. The statement said at least 64, so it would have to be 64 or the closet amount to 64 but it cannot be lower than 64. So there for 66 is the closest to the given amount, and in order for juan to get 64 he would need to take candies out for 11 days.

7 0

1 year ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

2 years ago

How much would $400 invested at 9% interest compounded continuously be worth after 3 years? Round your answer to the nearest cen

adell [148]

<span>In 3 years, you will have $523.97
</span><span>continuously = daily</span>

3 0

2 years ago

Read 2 more answers

Find the third, fifth, and seventeenth terms of the sequence described by each explicit formula

Sedaia [141]

Are you familiar with that?

7 0

2 years ago

Read 2 more answers

A new game is being introduced at the Hard Rock Cafe. A ball is spun around a wheel until it comes to rest in one of many spots.

andriy [413]

Answer:

$ 1.96

Step-by-step explanation:

Number of spots with outcome of $1 = 9

Number of spots with outcome of $2 = 18

Number of spots with outcome of $10 = 1

Total number of spots = 28

Probability that ball will land on $1 = $\frac{9}{28}$

Probability that ball will land on $2 = $\frac{18}{28}$

Probability that ball will land on $10 = $\frac{1}{28}$

The amount that player should expect to win on average in equal to expected value of the game. Expected value is calculated as the summation of product of probabilities with their respective outcomes.

i.e. for this case:

Expected Value will be:

$(1 \times \frac{9}{28})+(2 \times \frac{18}{28})+(10 \times \frac{1}{28})\\\\ =1.96$

This means, on average the player should expect to win $ 1.96

7 0

2 years ago