Solve <br> 3/4z-1/3=2/3z+1/5

Harry buys a TV priced at £1200 plus 20% VAT.

RoseWind [281]

Answer:

£ 114

Step-by-step explanation:

From the question given above, the following data were obtained:

Price of TV = £ 1200

VAT = 20%

Amount paid = £ 300

Amount paid monthly =.?

Next, we shall determine the VAT. This can be obtained as follow:

VAT = 20% of price of TV

VAT = 20/100 × 1200

VAT = £ 240

Next, we shall determine the total cost of the TV. This can be obtained as follow:

Price of TV = £ 1200

VAT = £ 240

Total cost of TV =?

Total cost = Price + VAT

Total cost = 1200 + 240

Total cost = £ 1440

Next, we shall determine the balance amount he needs to pay. This can be obtained as follow:

Total cost = £ 1440

Amount paid = £ 300

Balance amount =?

Balance = Total cost – Amount paid

Balance = 1440 – 300

Balance = £ 1140

Finally, we shall determine the amount Harry will pay month.

Balance Amount = £ 1140

Number of months = 10

Amount paid monthly =.?

Amount paid monthly = Balance / number of month

Amount paid monthly = 1140 / 10

Amount paid monthly = £ 114

Therefore, Harry will pay £ 114 monthly.

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{

il63 [147K]

Answer:

$\frac{x-3}{2x-3}$ . hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

$x^2-5x+6$

Now let's find what ac is (it's just c since a=1...)

$AC= 6$

List factors of -6

$\pm1, \pm2, \pm3, \pm6$ .

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

$(x-2)(x-3)$

Ok now let's factor the second equation:

$2x^2-7x+6$

Multiply a and c

$AC = 12$

List factors of 12:

$\pm1, \pm2, \pm3, \pm4, \pm6, \pm12$ .

Factors that add up to -7 and multiply to 12:

$-3\ and\ -4$

Rewrite equation:

$2x^2-4x-3x+6$

Group terms:

$(2x^2-4x)+(-3x+6)$

Factor out GCF:

$2x(x-2)-3(x-2)$

Rewrite:

$(2x-3)(x-2)$

Now let's write out the equation using these factors:

$\frac{(x-2)(x-3)}{(2x-3)(x-2)}$ .

Here we can factor out the x-2 and the simplified form is:

$\frac{x-3}{2x-3}$

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0

1 year ago

One study reports that 34% of newly hired MBAs are confronted with unethical business practices during their first year of empl

MaRussiya [10]

Answer:

$z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364$

$p_v =2*P(Z$

The p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.

Step-by-step explanation:

1) Data given and notation

n=116 represent the random sample taken

X represent the number graduates from the previous year claim to have encountered unethical business practices in the workplace

$\hat p=0.28$ estimated proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace

$p_o=0.34$ is the value that we want to test

$\alpha=0.05$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is 0.34 or no.:

Null hypothesis: $p=0.34$

Alternative hypothesis: $p \neq 0.34$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.28 -0.34}{\sqrt{\frac{0.34(1-0.34)}{116}}}=-1.364$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z$

The p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIl to reject the null hypothesis, and we can said that at 5% of significance the proportion of graduates from the previous year claim to have encountered unethical business practices in the workplace is not significant different from 0.34.

5 0

3 years ago

What is the missing reason in Step 7? Triangle angle sum theorem quadrilateral angle sum theorem definition of complementary con

Daniel [21]

Answer:

Hello your question is incomplete attached below is the complete question

Given: wxyz is a parallelogram, zx ≅ wy prove: wxyz is a rectangle what is the missing reason in step 7? a. triangle angle sum theorem. b. quadrilateral angle sum theorem. c. definition of complementary. d. consecutive ∠s in a ▱ are supplementary. 1. wxyz is a ▱; zx ≅ wy 1. given 2. zy ≅ wx 2. opp. sides of ▱ are ≅ 3. yx ≅ yx 3. reflexive 4. △zyx ≅ △wxy 4. sss ≅ thm. 5. ∠zyx ≅ ∠wxy 5. cpctc 6. m∠zyx ≅ m∠wxy 6. def. of ≅ 7. m∠zyx + m∠wxy = 180° 7. ? 8. m∠zyx + m∠zyx = 180° 8. substitution 9. 2(m∠zyx) = 180° 9. simplification 10. m∠zyx = 90° 10. div. prop. of equality 11. wxyz is a rectangle 11. rectangle ∠ thm.

answer: consecutive angles of any parallelogram are supplementary

Step-by-step explanation:

The missing reason in step 7 is : consecutive angles of any parallelogram are supplementary i.e. m∠ZYX + m∠WXY = 180°

<u>Reason </u>: ZY || WX also XY is the transversal line hence ∠wyx and ∠wxy are the consecutive angles on lines ZY and WX therefore m∠ZYX + m∠WXY = 180° ( sum of consecutive angles )

4 0

3 years ago

Read 2 more answers

One-fourth of a number and 6 is the same as 3 subtracted from the number itself

ratelena [41]

Answer:

I'm not the greatest at math but I'll see if I can get this right.

I'm super sorry if this is wrong

5 0

3 years ago

Solve 3/4z-1/3=2/3z+1/5