We use equations for geometric sequence. We do as follows:<span>
a(n) = a(1) r^(n-1)
20 = ar^(2-1)
</span>20 = ar<span>
a = 20/r
11.25= ar^(4-1)
</span>11.25 = ar^3
<span>11.25 = (20/r)r^3
r = 0.75
Hope this answers the question. Have a nice day.</span>
Answer:
The probability that the cost for someone's dog is higher than for the cat is 33.2%.
Step-by-step explanation:
With the data given, we know that the difference in cost of medical care of dogs and cats have a normal distribution with μ=-20 and σ=46.
To know the probability of the cost for the dog is higher than the cat, we have to calculate the probability of P(d>0).
Then we have to calculate z, and look up in a standarized normal distribution table.
Calculate z:

The probability of the difference being higher than 0, we have:

We can say that the probability that the cost for someone's dog is higher than for the cat is 33.2%.
Can’t help DDDD: bcoz link is a scam