4x - 1 < 11
Add 1 to both sides
4x < 12
Divide both sides by 4
x < 3
x is less than 3
Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval
The degrees of freedom is
df = n-1 = 19
We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.
The 99% confidence interval is
xbar +/- t*(s/√n)
t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)
Answer: The 99% confidence interval is (15.07, 19.93)
The answer is 6% because there wtv ur talking it it will equal to what your saying u feel me
Answer:
insufficient data
Step-by-step explanation:
please give complete question
In December she would have saved $1585 because 1235 + 250 = 1485. You can find how much money she raised in those 2 months by adding the totals of both months together, so 1485 + 1235 = 2720. She saved $2720 in the 2 months.
