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Serhud [2]
3 years ago
11

Please Help!!

Mathematics
1 answer:
valentina_108 [34]3 years ago
7 0

Answer:

1) The shoes were purchased at a 40% discount.

2) In order to treat 150 patients, the health department will require 9 vials of the malaria serum.

Step-by-step explanation:

1) If the original cost of the pair of shoes was $40, and you paid $24, then we want to set up a proportion to solve for the discounted percentage.

The discounted percentage is what you DID NOT pay, therefore we will find the amount of money saved first before setting up our proportion

$40 - $24 = $16

Meaning you did not pay that extra $16

Using that deficit, let's set up a proportion in terms of the total:

16/40 = 0.4

To find the percentage that was discounted we must multiply our proportion by 100%

0.4 *100% = 40%

Therefore, the shoes you had bought were on sale for 40% off.

2) If the health department expects 6 vials of malaria serum to treat 100 patients then our proportion of vials to patients becomes

6/100

To solve for how many vials will be required to treat 150 patients, we must equate our expected proportion to one with those 150 patients

6/100 = x/150          Where x denotes the number of vials needed.

                                Multiply both sides by 150 to isolate x

900/100 = x             Reduce the fraction

9 = x

Therefore, in order to treat 150 patients, the health department will require 9 vials of the malaria serum.

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Both spreads are best described by the standard deviation

Step-by-step explanation:

The given information are;

,                                    College                       High School

High,                              20                               20

Low,                                6                                 3

Q₁,                                   8                                 5.5

Q₃,                                  18                                16

IQR,                                 10                                10.5

Median,                           14                                11

Mean,                              13.3                             11

σ,                                      5.2                             5.4

Checking for outliers, we have

College

Q₁ - 1.5×IQR gives 8 - 1.5×10 = -7

Q₃ + 1.5×IQR gives 18 + 1.5×10 = 33

For high school

Q₁ - 1.5×IQR gives 5.5 - 1.5×10.5 = -10.25

Q₃ + 1.5×IQR gives 16 + 1.5×10.5 = 31.75

Therefore, there are no outliers and the data is representative of the population

From the data, for the college students, it is observed that the difference between the mean, 13.3 and Q₁, 8, and between Q₃, 18 and the mean,13.3 is approximately the standard deviation, σ, 5.2

The difference between the low and the high is also approximately 3 standard deviations

Therefore the college spread is best described by the standard deviation

Similarly for the high school students, the IQR is approximately two standard deviations, the  difference between the mean, 11 and Q₁, 5.5, and between Q₃, 16 and the mean,11 is approximately the standard deviation, σ, 5.4

Therefore the high school spread is also best described by the standard deviation.

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