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fgiga [73]
3 years ago
10

Marcia uses 5 ounces of chicken stock to make one batch of soup.She has a total of 400 ounces of chicken stock.How many batches

of soup can Marcia make
Mathematics
2 answers:
vodomira [7]3 years ago
6 0

Answer:

Marcia can make a total of 80 batches of soup

Step-by-step explanation:

400(total ounces)/5(ounces per batch)=80 batches

bulgar [2K]3 years ago
6 0

Answer:

80 batches of soup can Marcia .

Step-by-step explanation:

Given  : Marcia uses 5 ounces of chicken stock to make one batch of soup.She has a total of 400 ounces of chicken stock.

To find : How many batches of soup can Marcia make.

Solution : We have given

Marcia uses 5 ounces of chicken stock  =  1. batch of soup

Marcia uses 1 ounces of chicken stock = \frac{1}{5}.

Marcia uses 400 ounces of chicken stock =  \frac{400}{5}.

                                                                      = 80 batch of soup.

Therefore, 80 batches of soup can Marcia .

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Ludmilka [50]
Lets discern the infomation:

number_men = 165*0.6 = 99

so there are 99 men

non_fiction = 165 * 0.4 = 66

so 66 authors write non-fiction.

men writing non-fiction are 40, so 59 men write fiction, and 26 women write non-fiction.

probability of author non-fiction or man?
non-fiction: 40 men + 26 women = 66 total
man writers = 99

so in total 99 man + 26 women = 115 authors

hence the probability is:
115/165 = 69.6%
3 0
3 years ago
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slamgirl [31]
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7 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= 2 cm.
konstantin123 [22]

Consider right triangle ΔABC with legs AC and BC and hypotenuse AB. Draw the altitude CD.

1. Theorem: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

According to this theorem,

BC^2=BD\cdot AB.

Let BC=x cm, then AD=BC=x cm and BD=AB-AD=3-x cm. Then

x^2=(3-x)\cdot 3,\\ \\x^2=9-3x,\\ \\x^2+3x-9=0,\\ \\D=3^2-4\cdot (-9)=9+36=45,\\ \\\sqrt{D}=\sqrt{45}=3\sqrt{5},\\ \\x_1=\dfrac{-3-3\sqrt{5} }{2}0.

Take positive value x. You get

AD=BC=\dfrac{-3+3\sqrt{5} }{2}\ cm.

2. According to the previous theorem,

AC^2=AD\cdot AB.

Then

AC^2=\dfrac{-3+3\sqrt{5} }{2}\cdot 3=\dfrac{-9+9\sqrt{5} }{2},\\ \\AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

Answer: AC=\sqrt{\dfrac{-9+9\sqrt{5} }{2}}\ cm.

This solution doesn't need CD=2 cm. Note that if AB=3cm and CD=2cm, then

CD^2=AD\cdot DB,\\ \\2^2=AD\cdot (3-AD),\\ \\AD^2-3AD+4=0,\\ \\D

This means that you cannot find solutions of this equation. Then CD≠2 cm.

8 0
3 years ago
Read 2 more answers
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algol13

Answer:

x = - 9, x = 6

Step-by-step explanation:

Given

x² + 3x - 54

To find the solutions equate to zero

x² + 3x - 54 = 0 ← in standard form

(x + 9)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 9 = 0 ⇒ x = - 9

x - 6 = 0 ⇒ x = 6

7 0
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pav-90 [236]
I would think 32 so yea....because (12/98=49<33>**+{45-63-12{45+58-28} =32
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3 years ago
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