3/(x-1) - 1/(x^2-1) = 5/(x-1)
Subtract 3/(x-1) from both sides
-1/(x^2-1) = 2/(x-1)
Factor x^2 - 1
-1/[(x-1)(x+1] = 2/(x-1)
Multiply by (x-1)(x+1) on both sides
-1 = 2 (x+1)
-1 = 2x + 2
Subtract 2 from both sides
-3 = 2x
Divide by 2 on both sides
-3/2 = x
Hello!
To solve this question, find the roots and create test intervals.
Evaluation: -4<x<3/2
Have a wonderful day! :)
-L
Answer:
Taking P(x) = x³-12x-16 as an example
Step-by-step explanation:
For a polynomial, if
x = a is a zero of the function, then (x − a) is a factor of the function.
We have two unique zeros:
−2 and 4. However, −2 has a multiplicity of 2, which means that the factor that correlates to a zero of −2 is represented in the polynomial twice.
Following how it's constructed
zero at -2, multiplicity 2
zero at 4, multiplicity 1
p(x)=x−(−2))²(x−4)¹
Thus,p(x)=(x+2)²(x−4)
Expand: p(x)=(x²+4x+4)(x−4)
p(x) =x³−12x−16
Answer:
$88
Step-by-step explanation:
-38+126=$88