Friday's high temperature was -1 C. The temperature was -5 C. What was the difference between the high and low temperature?

The troupe’s account balance first reached $500 on Day 4. The last day the account balance was $500 was

morpeh [17]

Answer:

<u><em>The answer is c, hope this helps</em></u>

Step-by-step explanation:

7 0

2 years ago

Which is an equation of the line that passes through the point (8,7) and is perpendicular to the line whose equation is y = 4x-1

algol [13]

Answer:

Y = -1/4x + 5

Step-by-step explanation:

7 0

3 years ago

mrs. West took her class on a field trip to the museum cost of admission for the girls was $90 and the cost of admission for the

timofeeve [1]

Answer:

15 dollars

Step-by-step explanation:

4 0

3 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

So

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$

Here

$\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(Z < 2.37 ) - P(Z < -2.37 )$

From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is

$P(Z < 2.37 ) = 0.9911$

and

$P(Z < - 2.37 ) = 0.0089$

So

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) =0.9911-0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = 0.9822$

=> $P(| \^ p - p| < 0.05 ) = 0.9822$

3 0

3 years ago

The credit department of Lion's Department Store in Anaheim, California, reported that 30% of their sales are cash, 30% are paid

Oliga [24]

Answer:

Hence the probability that she paid cash is 0.105

Step-by-step explanation:

P(cash) = 0.3

P(credit card ) = 0.3

P(debit card ) = 0.4

P ( more than $50 | cash ) = 0.2

P (more than $50 | credit card ) =0.9

P (more than $ 50 |debit card ) = 0.6

P ( more than $50) = P ( more than $50 | cash )* P (cash) + P (more than $50 credit card ) * P(credit card ) + P (more than $ 50 |debit card )* P(debit card )

= 0.2 * 0.3 + 0.9 * 0.3 + 0.6* 0.4

= 0.57

P ( more than $50) = P ( more than $50 | cash )* P (cash) / P ( more than $50)

= 0.2* 0.3 / 0.57

= 0.105

6 0

3 years ago