A
. retaining gases around Earth to form the atmosphere ... gravity
B. stratifying the atmosphere into layers ... gravity
C. movements of tectonic plates ... gravity & buoyancy
D. spreading of the sea floor ... gravity & buoyancy
E. deflecting cosmic rays ... <em>Earth's magnetic field</em>
Its b
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Answer:
Drift velocity of conduction electrons in Gold = 8.73 × 10⁻⁶ m/s = 8.73 μm/s
Explanation:
Drift velocity, v, is given by
v = I/(nAq)
where v = drift velocity
I = current in the wire
n = number of electrons per cubic metre for the wire
A = Cross sectional Area of the wire
q = charge on one electron
I = 0.373 A
A = πD²/4 = π(0.0024)²/4 = 4.52 × 10⁻⁶ m²
q = 1.602 × 10⁻¹⁹ C
n = 5.90 × 10²⁸ electrons/m³
v = 0.373/(5.90 × 10²⁸ × 4.52 × 10⁻⁶ × 1.602 × 10⁻¹⁹) = 8.73 × 10⁻⁶ m/s
Answer:
Newton's Third Law of Motion
Explanation:
Newton's Third Law of Motion which states that, for every action there is an equal but opposite reaction.
This ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects.
In this scenario, a ball bounced by a basketball player on the floor bounces back up at her.
According to Newton's Third Law of Motion, the statement above simply means that in every interaction, there is a pair of forces acting on the two interacting objects i.e the ball and floor. The size of the force on the ball equals the size of the force on the floor. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.
Hence, the ball bounced by the basketball player on the floor would bounce back in equal magnitude.