a 10kg flowerpot is suspended from the end of a horizontal strut by a cable attached at 30° above the horizontal. If the strut h
as no mass what is tension in the cable
1 answer:
T = tension force in the cable
m = mass of the flowerpot = 10 kg
θ = angle cable makes with the horizontal = 30 deg
there are horizontal and vertical components of tension force . The vertical component of tension force in cable is in opposite direction of the weight of the flowerpot. hence vertical component of tension balances the weight of flowerpot. so we can write
T Sinθ = mg
inserting the above value
T Sin30 = 10 x 9.8
T(0.5) = 98
T = 98/0.5
T = 196 N
You might be interested in
Answer:
Explanation:
Given that,
Mass of the heavier car m_1 = 1750 kg
Mass of the lighter car m_2 = 1350 kg
The speed of the lighter car just after collision can be represented as follows
b) the change in the combined kinetic energy of the two-car system during this collision
substitute the value in the equation above
Hence, the change in combine kinetic energy is -2534.78J