a 10kg flowerpot is suspended from the end of a horizontal strut by a cable attached at 30° above the horizontal. If the strut h
as no mass what is tension in the cable
1 answer:
T = tension force in the cable
m = mass of the flowerpot = 10 kg
θ = angle cable makes with the horizontal = 30 deg
there are horizontal and vertical components of tension force . The vertical component of tension force in cable is in opposite direction of the weight of the flowerpot. hence vertical component of tension balances the weight of flowerpot. so we can write
T Sinθ = mg
inserting the above value
T Sin30 = 10 x 9.8
T(0.5) = 98
T = 98/0.5
T = 196 N
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Answer:
Check the explanation
Explanation:
When we have an object in periodic motion, the amplitude will be the maximum displacement from equilibrium. Take for example, when there’s a back and forth movement of a pendulum through its equilibrium point (straight down), then swings to a highest distance away from the center. This distance will be represented as the amplitude, A. The full range of the pendulum has a magnitude of 2A.
position = amplitude x sine function(angular frequency x time + phase difference)
x = A sin(ωt + ϕ)
x = displacement (m)
A = amplitude (m)
ω = angular frequency (radians/s)
t = time (s)
ϕ = phase shift (radians)
Kindly check the attached image below to see the step by step explanation to the question above.
