a 10kg flowerpot is suspended from the end of a horizontal strut by a cable attached at 30° above the horizontal. If the strut h
as no mass what is tension in the cable
1 answer:
T = tension force in the cable
m = mass of the flowerpot = 10 kg
θ = angle cable makes with the horizontal = 30 deg
there are horizontal and vertical components of tension force . The vertical component of tension force in cable is in opposite direction of the weight of the flowerpot. hence vertical component of tension balances the weight of flowerpot. so we can write
T Sinθ = mg
inserting the above value
T Sin30 = 10 x 9.8
T(0.5) = 98
T = 98/0.5
T = 196 N
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Answer:
The new potential energy decreases by the factor of 2 to the old potential energy.
Explanation:
Capacitance of a parallel plate capacitor is given by the relation :
C = (ε₀A)/d
Here ε₀ is vacuum permittivity, A is area of the capacitor plate and d is the distance between them.
Potential energy of the capacitor, U =
Here V is the potential difference between the plates.
According to the problem, the distance between the plates get double but area remains same. So,
d₁ = 2d
Here d₁ is new distance between the plates.
Hence, new capacitance is :
C₁ = (ε₀A)/d₁ = (ε₀A)/2d = C/2
The capacitor have same potential difference that is V. Hence, the new potential energy is :
U₁ = =
U₁ = U/2