a 10kg flowerpot is suspended from the end of a horizontal strut by a cable attached at 30° above the horizontal. If the strut h
as no mass what is tension in the cable
1 answer:
T = tension force in the cable
m = mass of the flowerpot = 10 kg
θ = angle cable makes with the horizontal = 30 deg
there are horizontal and vertical components of tension force . The vertical component of tension force in cable is in opposite direction of the weight of the flowerpot. hence vertical component of tension balances the weight of flowerpot. so we can write
T Sinθ = mg
inserting the above value
T Sin30 = 10 x 9.8
T(0.5) = 98
T = 98/0.5
T = 196 N
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Explanation:
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where,
M = Magnification = 4
q = image distance = 5 m
p = object distance = ?
Therefore,
Now using thin lens formula:
<u>f = 1 m</u>